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LUCKY_DIMON [66]
2 years ago
9

Please help I need it

Mathematics
1 answer:
S_A_V [24]2 years ago
7 0

Answer:

13/48

Step-by-step explanation:

I take the middle sign to be plus.\

3/4//4/5 = 3/4 * 5/4 = 15/16

15/16 - 2/3 =

The lowest common denominator would be 48: 16 and 3 are prime to each other.

45/48 - 32/48 = 13 / 48

Where did the minus come from? I take it that there is a minus sign in front of the 2

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Simplify (x^2y)^3. <br> 1)X^2y^3<br> 2)x^5y^3<br> 3)x^6y^3
dsp73

Answer:

the answer is 2

Step-by-step explanation:

3 0
3 years ago
What is the row echelon form of this matrix?
USPshnik [31]

The row echelon form of the matrix is presented as follows;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

\begin{bmatrix}-3 &6  &15  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

The conditions of a matrix in the row echelon form are as follows;

  1. There are row having nonzero entries above the zero rows.
  2. The first nonzero entry in a nonzero row is a one.
  3. The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

\begin{bmatrix}1 &-2  &-5  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 1&0  &-1  \\\end{bmatrix}

Subtracting Row 1 from Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&2  &4  \\\end{bmatrix}

Adding Row 2 to Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&0  &18  \\\end{bmatrix}

Dividing Row 2 by -2, and Row 3 by 18 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

The above matrix is in the row echelon form

Learn more about the row echelon form here:

brainly.com/question/14721322

#SPJ1

8 0
1 year ago
How would the factor pairs change if nancy had only 5 posters to arrange?
Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0
3 years ago
number of bacteria in a certain population Increases according to a continuous exponential growth model with How many hours does
vladimir1956 [14]

Answer:

It takes 1.77 hours for the population to double.

Step-by-step explanation:

Equation for population growth:

The equation for population growth, after t hours, with a growth rate parameter of r, as a decimal, is given by:

P(t) = P(0)(1+r)^t

Growth rato parameter of 48% per hour

This means that r = 0.48. So

P(t) = P(0)(1+r)^t

P(t) = P(0)(1+0.48)^t

P(t) = P(0)(1.48)^t

How many hours does it take the size of the sample to double?

This is t for which P(t) = 2P(0). So

P(t) = P(0)(1.48)^t

2P(0) = P(0)(1.48)^t

(1.48)^t = 2

\log{(1.48)^t} = \log{2}

t\log{1.48} = \log{2}

t = \frac{\log{2}}{\log{1.48}}

t = 1.77

It takes 1.77 hours for the population to double.

3 0
3 years ago
Whaaaaaaaaaaaaat????
IrinaK [193]

9514 1404 393

Answer:

  7 pizzas

Step-by-step explanation:

For a difference in price of $58 -25 = $33, a customer gets a difference in number of 5 -2 = 3 pizzas. Then a pizza costs $33/3 = $11.

The cost of 2 pizzas is $22, so the delivery charge is $25 -22 = $3.

For $80, after subtracting the $3 delivery charge, $77 goes to the cost of pizzas. For that amount, $77/$11 = 7 pizzas will be delivered.

3 0
3 years ago
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