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umka2103 [35]
3 years ago
7

Plzzzz help me!!!Plz don't steal my points or add a link​

Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer: What do you mean? if you till me i can help you

Step-by-step explanation:

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A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then
Masja [62]
A.
\frac{7purple}{9total} *  \frac{2white}{8total}  \\  \frac{14}{72}  \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} *  \frac{1white}{8total}  \\  \frac{2}{72}  \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
<u />\frac{7purple}{9total} *  \frac{6purple}{8total}  \\  \frac{42}{72}  \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
<u>Chance of selecting two purple</u> vs. <em>Chance of Selecting 2 white:</em>
<u>0.583</u>><em>0.278</em>.
It is more likely to select 2 purple marbles.

Hope this helps!
6 0
3 years ago
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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

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3 years ago
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I don’t get this can someone please help me?
FinnZ [79.3K]
The price difference/ the original price and times the whole equation by 100 (to get the percentage).

> ($50/$150) x 100 = 33% (rounded)
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3 years ago
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How the flibberdoodle do you graph decimals on a coordinate graph?!!
Annette [7]
Plotting coordinates can be a little confusing, but it doesn't have to be as long as you remember a few important details. The first number in the coordinate set tells you how far right (for a positive number) or left (for a negative number) you need to travel on the x-axis. The second number in the coordinate set tells you how far up (for a positive number) or down (for a negative number) you need to travel on the y-axis. Any set of coordinates can be represented by the variables x and y. If you picture (x, y), it will help you remember the x-coordinate comes first, so you will travel either right or left before travelling up or down.

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Help for brainliest plz
Illusion [34]

Answer:

500

Step-by-step explanation:

Equations =4÷3×3.14×5×5×5

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3 years ago
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