Since there are no actual values, I guess we just have to isolate the b.
2A=bh (multiply both sides by 2)
2A/h=b (divide by h)
hope this helps
Clara forgot to distribute the - sign to- (2b-r) through all the terms the answer would be 6b+3r
Sorry I really need point but I wish you good luck!
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =
=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
Answer:
x1 = 2, y1 = 0
x2 = 2, y2 = 6
Step-by-step explanation:
Each pair of coordinates is (x, y). The first pair is (x1, y1). The second pair is (x2, y2). This means you have ...
x1 = 2, y1 = 0
x2 = 2, y2 = 6
_____
<em>Additional comment</em>
The slope of the line through these points is ...
m = (y2 -y1)/(x2 -x1) = (6 -0)/(2 -2) = 6/0 = undefined
The line through these points is a vertical line with equation x = 2.
