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TEA [102]
3 years ago
9

What is the following product? 3 root 5 times root 2

Mathematics
2 answers:
svet-max [94.6K]3 years ago
5 0

Answer:

\sqrt[6]{200}

Step-by-step explanation:

First of all, you need to know that you cannot multiply those radicals without having a common index (the little number outside the radical that sits in the curve of the radical).  One is a 3 and the other, without being stated outright, is understood to be a 2.  BUT we can make them like.  The index of a radical is the denominator of the exponential equivalent.  

\sqrt[3]{5}=5^{\frac{1}{3}} and

\sqrt{2}=2^{\frac{1}{2}}

See how the indexes are now the denominators of the rational exponents.  We can make them like by finding the LCM of 3 and 2...which is 6:

5^{\frac{1}{3}}=5^{\frac{2}{6}} and

2^{\frac{1}{2}}= 2^{\frac{3}{6}}

Now that the indexes are like, we rewrite them as radicals again:

\sqrt[6]{5^2}*\sqrt[6]{2^3} which, simplified, is

\sqrt[6]{25}*\sqrt[6]{8}

Now we can find the product which is

\sqrt[6]{200}

Crazy boy [7]3 years ago
3 0

\bf \textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{5}\cdot \sqrt{2}\implies \sqrt[3]{5^1}\cdot \sqrt[2]{2^1}\implies 5^{\frac{1}{3}}\cdot 2^{\frac{1}{2}}\implies 5^{\frac{2}{6}}\cdot 2^{\frac{3}{6}}\implies \sqrt[6]{5^2}\cdot \sqrt[6]{2^3} \\\\\\ \sqrt[6]{25}\cdot \sqrt[6]{8}\implies \sqrt[6]{25\cdot 8}\implies \sqrt[6]{200}

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