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yaroslaw [1]
3 years ago
5

Help me plz it’s number 11 I need this urgent

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

f = -9

Step-by-step explanation:

3(x)

3(-9)

-27

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Anyone know how to solve?
sergejj [24]

Answer:

was there more

Step-by-step explanation:

(i will edit answer)

3 0
3 years ago
2.1 , - 6/10 , -9/4 , -0.75 , 5/3 , least to greatest
WINSTONCH [101]

Answer:

-9/4, -0.75, -6/10, 5/3, 2.1

Step-by-step explanation:

This is a lot easier to figure out if you simplify the fractions and then change them to decimals

So -9/4 = -2 1/4 or -2.25

-0.75

-6/10 = -0.60

5/3 = 1 2/3 or 1.67

2.1

When you are ordering negatives, the biggest negative is the least. That is why -9/4 (-2.25) is the least number out of the five given.

The next one would be -0.75, because it is the second biggest negative fraction.

The next one is -0.60 because that is the 3rd biggest negative fraction (or the smallest because this is the last negative)

Now, because we're in the positives we start with 1.67, because it is smaller than the other number.

2.1 is our last number, so it is the greatest!

I hope this helped :)

6 0
4 years ago
Pls tell me so quotes of not giving up
lesantik [10]

Answer:

Step-by-step explanation:

Knowledge is knowing a tomato is a fruit, wisdom is not putting it in a fruit salad

Your time is too valuable to waste on those who don't deserve it

Never give up great things take time

Failure is not an acception

As a wise fish once said "Just Keep Swimming" the more u swim the closer you get to your goal.

4 0
3 years ago
Find the area of the figure.
Otrada [13]

Answer:

20 square units

Step-by-step explanation:

The figure shows a triangle whose;

  • Base AC is 8 units
  • Height is 5 units

We are supposed to get its area;

Area of a triangle is given by the formula;

Area = 0.5×b×h

Thus;

Area = 0.5 × 8 units × 5 units

        = 20 square units

Hence, the area of the figure is 20 square units

8 0
4 years ago
Simplify<br> 7^2x^-3y/49x^-3y^-2
olya-2409 [2.1K]
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
4 0
4 years ago
Read 2 more answers
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