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3 years ago

Please can someone help me

Mathematics

1 answer:

disa [49]3 years ago

3 0

Answer:

I believe your answer is correct.

Step-by-step explanation:

You might be interested in

Help please:

s344n2d4d5 [400]

➽━━━━━━━━━━━━━──➸

☺ Hello mate__ ❤

◾◾here is your answer...

i think right question is this

(3x − 7y)^2

ok now start solving:-

(3x − 7y)^2

=> (3x − 7y) (3x − 7y)

=> 3x(3x- 7y) -7y(3x-7y)

=>. 3x.3x - 3x.7y-7y. 3x + 7y.7y

=> 9x^2 -27xy +27xy + 49y^2

=> 9x^2 + 49y^2

so your correct ans. is 9x2 + 49y2

➽━━━━━━━━━━━━━──➸

I hope, this will help you.☺

Thank you______❤

✿┅═══❁✿ Be Brainly✿❁═══┅✿

7 0

4 years ago

Penny reads 13 pages in 1/3 hour. What is the unit rate for pages per hour? For hours per page?

Free_Kalibri [48]

39 pages per hour
13x3=39

8 0

2 years ago

Read 2 more answers

Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x

Mrac [35]

Answer:

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

Step-by-step explanation:

The given functions are $f(x)=\frac{3x-1}{x-4}$ and $g(x)=\frac{x+1}{x}$ .

We now composed the two functions to find:

$(f\circ g)(x)=f(g(x))$

$\implies (f\circ g)(x)=f(\frac{x+1}{x})$

$\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}$

$\implies (f\circ g)(x)=\frac{4x+3}{1-3x}$

This function is defined if the denominator is not zero.

$1-3x\ne0$

$x\ne\frac{1}{3}$

We write this in interval notation as:

$(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)$

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of $(f\circ g)(x)$ is

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

4 0

3 years ago

What is the coefficient of x in 4+3y²+x?

Anni [7]

the coefficient of x is 1

8 0

1 year ago

Rewrite the the expression using as few terms as possible. X^2+5x+4x+20

Effectus [21]

Answer:

x^2 + 9x + 20

Step-by-step explanation:

x^2 + 5x + 4x + 20

x^2 + 9x + 20

all u have to do is combine liked terms

8 0

3 years ago