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ddd [48]
3 years ago
7

5 Four children all play a computer game on the first day of the year. Then Anne plays every second day, Bernard plays every thi

rd day, Charles plays every fourth day and Danielle only plays every fifth day. What is the date when they next all play on the same day? b On how many days of the year do they all play on the same day?
Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0
Ednesday (9 weeks later) = 10th October.
ep-by-step explanation:
e label the days with the initials of the
imes.
M= 4
D=7
B=6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need
to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it
would be 84 days after this event.
18+84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th
October
We can check 84 days = 9 weeks
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Given the equation:

y=x^2-x-6

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• x-intercept:

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To find the x-intercepts, substitute 0 for y and solve for x.

We have:

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Subtract 2 from both sides:

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Therefore, the x-intercepts are:

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• y-intercept:

The y-intercept is the point where the parabola crosses the y-axis. The x-value at the y-intercept is zero.

To find the y-intercept, substitute 0 for x and solve:

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In point form:

x-intercept: (3, 0), (-2, 0)

y-intercept: (0, -6)

ANSWER:

A. The x-intercepts are (3, 0), (-2, 0)

A. The y-intercept is (0, -6)

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