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storchak [24]
3 years ago
9

5. Which coefficients correctly balance the formula equation

Chemistry
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

which of these sentences contains a correctly formed possessive form of the name andres

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In a chemical laboratory, a mortar and pestle function is to decrease surface area of a solute. The correct answer is B.
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What is the mass percent of chlorine in chlorine flouride if 5.753g of chlorine and 9.248g of fluorine combine to create chorine
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4.254g

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¿Cuántos moles de C3H8 contienen 9.25 x 10^24 moléculas?
Igoryamba

Answer:

\large \boxed{\text{e. 15.4 mol C$_{3}$H}_{8}}

Explanation:\text{Moles of propane} = 9.25 \times 10^{24}\text{ molecules} \times \dfrac{\text{1 mol }}{6.022 \times\ 10^{23} \text{molecules}} = \textbf{15.4 mol}

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2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
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Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
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C = 1137 J / 140 * 36.2

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8 0
3 years ago
A mixture containing 20 mole % butane, 35 mole % pentane and rest
notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB

Whereas y accounts for the fractions at the outlet distillate and x for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

0.9=\frac{y_bD}{z_bF}

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

y_bD=0.9*z_bF=0.9*0.2*100mol=18mol

The total distillate flow:

y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol

And the total bottoms flow:

F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025

Then, the molar fraction of pentane and hexane:

x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422

x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

8 0
3 years ago
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