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3 years ago

Can anyone help me please

Chemistry

2 answers:

Mice21 [21]3 years ago

8 0

Answer:

Nucleic acids

Explanation:

all organic foods (fruit, meat, etc) contain it to some degree. because all organic foods have dna in them.

OLEGan [10]3 years ago

4 0

Nucleic acids

To some extent, it can be found in all organic foods (fruit, meat, etc.). Because dna is present in all organic foods.

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What do i do if my crush likes another girl?

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Answer: tell that person how u feel

Explanation: If it doesn’t go well ask if u can just stay friends

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3 years ago

Read 2 more answers

11. Propane (C3Hg) is a fuel commonly used in gas grills.

Mrac [35]

Answer:

81.71%

Explanation:

One mole of propane contains 3 moles of carbon atoms and 8 moles of hydrogen atoms, as seen from the molecular formula of $C_3H_8$ . In order to calculate the percent of carbon in propane by mass, we need to remember that %w/w (or percent mass) formula states that:

$\omega=\frac{m_{component}}{m_{total}}\cdot100\%$

That is, we need to divide the mass of the component of interest by the total mass of the compound and multiply by 100 to obtain the percentage.

For simplicity, let's take 1 mole of propane and find the mass of 1 mole (hence, we'll be finding the molar mass of propane). To do that, we add the 3 molar masses of carbon and 8 molar masses of hydrogen to obtain a total of:

$M_{C_3H_8}=3M_C+8M_H=3\cdot12.011 \frac{g}{mol}+8\cdot1.00784\frac{g}{mol}=44.096 \frac{g}{mol}$

Now that we have the molar mass of propane, we also need to find the total mass of carbon in 1 mole of propane. We know that we have a total of 3 moles of carbon which corresponds to:

$M_C=3\cdot12.011 \frac{g}{mol}=36.033 \frac{g}{mol}$

Dividing the mass of carbon present by the total mass of the compound will yield the mass percentage as defined by the formula we introduced:

$\omega_C=\frac{36.033\frac{g}{mol}}{44.096 \frac{g}{mol}}\cdot 100\%=81.71\%$

5 0

3 years ago

The standard free energy of formation, ΔG∘f, of a substance is the free energy change for the formation of one mole of the subst

OLEGan [10]

Answer:

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG∘f=−451.0 kJ/mol

D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol

Explanation:

The spontaneity of a reaction is given by the value of the standard Gibbs free energy of the reaction (ΔG°rxn). The more negative is the ΔG°rxn, the more spontaneous is a reaction.

The ΔG°rxn can be calculated using the following expression:

ΔG°rxn = ∑np × ΔG°f(products) − ∑nr × ΔG°f(reactants)

By definition, the standard Gibbs free energy of formation of simple substances in their most stable state is zero. That is why, in the reaction of formation of a compound ΔG°rxn = ΔG°f(product).

<em>Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? </em>

<em> </em>Not feasible. ΔG°rxn = ΔG°f(product) > 0.

Feasible. ΔG°rxn = ΔG°f(product) < 0.

Not feasible. ΔG°rxn = ΔG°f(product) > 0.

Feasible. ΔG°rxn = ΔG°f(product) < 0.

3 0

4 years ago

What volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid?

kirza4 [7]

The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 15.7 M
Volume of diluted solution (V₂) = 12 L
Molarity of diluted solution (M₂) = 0.156 M
Volume of stock solution needed (V₁) = ?

<h3>How to determine the volume of the stock solution needed</h3>

The volume of the stock solution needed can be obtained by using the dilution formula as shown below:

M₁V₁ = M₂V₂

15.7 × V₁ = 0.156 × 12

15.7 × V₁ = 1.872

Divide both side by 15.7

V₁ = 1.872 / 15.7

V₁ = 0.12 L

Thus, the volume of the stock solution needed to prepare the solution is 0.12 L

Learn more about dilution:

brainly.com/question/15022582

#SPJ1

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1 year ago

Note.... the colliding molecules must possess certain minimum energy (threshold energy)to make the collision effective n..the ad

Oliga [24]

Answer:

<h3>I think, answer is threshold energy.</h3>

<h3>activation energy. </h3>

Explanation:

<h3>Hope it helps you....</h3>

<h2>Thank you..</h2>

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3 years ago