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ICE Princess25 [194]
3 years ago
5

How do emulsifiers help oil and water to mix and not separate?

Chemistry
1 answer:
Olin [163]3 years ago
3 0

Answer:

To prevent the mixture from separating substances called emulsifiers can be added. These help to form and stabilise the emulsions, preventing or slowing the water and fat/oil from separating. ... The hydrophilic end of the emulsifier molecule is attracted to the water and the hydrophobic end is attracted to the fat/oil.

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From a scientific viewpoint, why do many desert dwellers elect to wear white or light-colored garments
alexandr1967 [171]
Darker colors absorb sunlight more, so it will become hotter. Lighter colored clothes will better reflect sun so they will be less hot.

Hope that helped
7 0
3 years ago
What is the relationship between the reactant and yield
solong [7]
Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful
7 0
4 years ago
What does it mean for heat to be transferred by radiation?
iris [78.8K]

Answer:

Here's what I get  

Explanation:

It means that the heat comes directly at you without relying  on any material to conduct it.

For example, you feel the heat from a campfire even if the wind is blowing crosswise to you and the fire.

5 0
4 years ago
Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
3 0
4 years ago
Read 2 more answers
If I want to lower the volume (loudness) I can do which of the following. Select all that apply.
nirvana33 [79]

Sound travels in waves and the height of the wave is the loudness of the sound.

To decrease sound, you need to make the waves not so high, so you can

- decrease the amplitude

- decrease the height of the crest   (lower the top of the wave down)

- increase the height of the trough  (bring the bottom of the wave up)

It's all about getting the wave to be closer to the center, to not be so high and low, but to be flatter.

(picture taken from sound . eduation website)

6 0
3 years ago
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