Simplify. (−5p4z6u)3

Consider the following sets: R = {x | x is the set of rectangles} P = {x | x is the set of parallelograms} T = {x | x is the set

Liula [17]

"T is a subset of P"

Not true since triangle has three sides but parallelogram has four sides.

"E is a subset of I"

True since equilateral triangles are isosceles triangles with all angles equal.

"S is a subset of T"

True since scalene triangles are still triangle.

"I ⊂ E"

False since there are isosceles triangles those are not equilateral triangles. Namely triangle with angles 20°, 20°, 140°

"T ⊂ E"

False since not all triangles are equilateral. Scalene triangle is one of counterexamples.

"R ⊂ P"

True since rectangles are parallelograms with right angles.

Final answer: <span>E is a subset of I, </span>S is a subset of T, and R ⊂ P.

Hope this helps.

6 0

3 years ago

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Every weekend, Morgan buys interesting clothes at her local thrift store and then resells them on an auction website. If she bri

Artyom0805 [142]

150 - s <== ur expression

when s = 27.13
150 - 27.13 = 122.87

when s = 55.14
150 - 55.14 = 94.86

6 0

3 years ago

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A bag of oranges weighs 5 1/4 pounds. How much does 1 1/2 bags weigh?

Andreyy89

Answer:

you simplify the fractions then you cross multiply

Step-by-step explanation:

1/2 * 4/2 you multiply 1 and 4 and you get 4/4 which is equal to 1

3 0

3 years ago

Consider the following function. f(x) = 7x + 1 x (a) Find the critical numbers of f. (Enter your answers as a comma-separated li

sukhopar [10]

Answer:

a) DNE

b) The function increases for every real value of x.

c) DNE

Step-by-step explanation:

Given a function f(x), the critical points are those in which $f^{\prime}(x) = 0$ , that is, the roots of the first derivative of f(x).

Those critical points let us find the intervals in which the function increases or decreases. If the first derivative in the interval is positive, the function increases in the interval. If it is negative, the function decreases.

If the function increases before a critical point and then, as it passes the critical point, it starts to decrease, we have that the critical point $(x_{c}, f(x_{c}) is a relative maximum.If the function decreases before a critical point and then, as it passes the critical point, it starts to increase, we have that the critical point [tex](x_{c}, f(x_{c}) is a relative minimum.If the function has no critical points, it either always increases or always decreases.In this exercise, we have that:[tex]f(x) = 7x + 1$

(a) Find the critical numbers of f.

$f^{\prime}(x) = 0$

$f^{/prime}(x) = 7$

7 = 0 is false. This means that f has no critical points.

(b) Find the open intervals on which the function is increasing or decreasing.

Since there are no critical points, we know that either the function increases or decreases in the entire real interval.

We have a first order function in the following format:

$f(x) = ax + b$

In which $a > 0$ .

So the function increases for every real value of x.

(c) Apply the First Derivative Test to identify the relative extremum.

From a), we find that there are no critical numbers. So DNE

7 0

3 years ago

Pls help brainlist pls help

Len [333]

Answer:

1. V = 157in³, so the volume of the sugar container is 157in³

2. h = 12in, so the height of the rice container is 12in

3. The rice container's height is 12in and the height of the sugar container is 8in, which means the rice container is taller by 4in. The rice container's volume is 235.5in and the sugar container's volume is 157in, so the rice container's volume is greater than the volume of the sugar container's volume by 78.5in.

4. V = 50.24in³, so the volume of the flour container is 50.24in³

5. The rice container's volume is 235.5in, the sugar container's volume is 157in, and the flour container's volume is 50.24in. This means the container that contains the greatest volume is the rice container and the container that contains the smallest volume is the flour container.

Step-by-step explanation:

1. to find the volume of a cylinder, we use the formula:

V = πr²h

V = 3.14(2.5² × 8)

V = 3.14(6.25 × 8)

V = 3.14(50)

V = 157in³

2. To find the height of a cylinder when given the volume and radius, you use the formula:

h = V / πr²

h = 235.5/3.14(2.5²)

h = 235.5/3.14(6.25)

h = 235.5/19.625

h = 12in

h = height

3. The rice container's height is 12in and the height of the sugar container is 8in, which means the rice container is taller by 4in. The rice container's volume is 235.5in and the sugar container's volume is 157in, so the rice container's volume is greater than the volume of the sugar container's volume by 78.5in.

4.

V = bh

V = 12.56 × 4

V = 50.24in³

5. The rice container's volume is 235.5in, the sugar container's volume is 157in, and the flour container's volume is 50.24in. This means the container that contains the greatest volume is the rice container and the container that contains the smallest volume is the flour container.

5 0

2 years ago