Answer:
<h2>4 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{2.41 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.00322...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B2.41%20%5Ctimes%20%20%7B10%7D%5E%7B24%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%204.00322...)
We have the final answer as
<h3>4 moles</h3>
Hope this helps you
Answer:
= 0.014 g of BaCO3
Explanation:
Let x = mol/L of BaCO3 that dissolve.
This will give;
x mol/L Ba2+ and x mol/L CO32-
But;
Ksp = 5.1x10^-9.
Therefore;
Ksp = 5.1 x 10^-9 = (x)(x)
Thus;
x = molar solubility
= √ (5.1 x 10^-9)
= 7.1 x 10^-5 M
Therefore;
Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol
= 0.014 g
Answer: The oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.
Explanation:
Given:
= 2 L,
= 2 atm
= 1 L,
= ?
Formula used to calculate the new pressure is as follows.
![P_{1}V_{1} = P_{2}V_{2}](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%20%3D%20P_%7B2%7DV_%7B2%7D)
Substitute the values into above formula as follows.
![P_{1}V_{1} = P_{2}V_{2}\\2 atm \times 2 L = P_{2} \times 1 L\\P_{2} = 4 atm](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%20%3D%20P_%7B2%7DV_%7B2%7D%5C%5C2%20atm%20%5Ctimes%202%20L%20%3D%20P_%7B2%7D%20%5Ctimes%201%20L%5C%5CP_%7B2%7D%20%3D%204%20atm)
Thus, we can conclude that the oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.