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Mathematics

1 answer:

ikadub [295]3 years ago

3 0

Answer:

79 minutes

Step-by-step explanation:

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Use the vertical line test to determine which graph does not represent a function. On a coordinate plane labeled Graph A, a para

padilas [110]

Ggggggggggggggggggggg ggggggggggggghwoangsksvjslsnbd

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3 years ago

Which point lies on a circle that is centered at A(-3, 2) and passes through B(1, 3)?

My name is Ann [436]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the center
r - the radius

$\hbox{the center: } A(-3,2) \\
h=-3 \\ k=2 \\ \\
\hbox{the equation:} \\
(x+3)^2+(y-2)^2=r^2 \\ \\
\hbox{the circle passes through B(1,3)} \\
x=1 \\ y=3 \\ \Downarrow \\
(1+3)^2+(3-2)^2=r^2 \\
4^2+1^2=r^2 \\
16+1=r^2 \\
17=r^2 \\ \\
\hbox{the equation is:} \\
(x+3)^2+(y-2)^2=17$

Plug the coordinates of the points into the equation and check:
$C(-1,-2) \\
(-1+3)^2+(-2-2)^2=17 \\
2^2+(-4)^2=17 \\
4+16=17 \\
20=17 \\
not \ true \\ \\
D(-6,3) \\
(-6+3)^2+(3-2)^2=17 \\
(-3)^2+1^2=17 \\
9+1=17 \\
10=17 \\
not \ true$

$E(-3,-3) \\
(-3+3)^2+(-3-2)^2=17 \\
0^2+(-5)^2=17 \\
25=17 \\
not \ true \\ \\
F(-2,6) \\
(-2+3)^2+(6-2)^2=17 \\
1^2+4^2=17 \\
1+16=17 \\
17=17 \\
true$

The answer is F(-2,6).

8 0

3 years ago

What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of −12?

Lerok [7]

$a_1=4;\ a_2=-12\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{-12}{4}=-3$

The formula of a geometric sequence:

$a_n=a_1\cdot r^{n-1}$

substitute

$a_n=4\cdot(-3)^{n-1}$

$The\ domain:\ \text{all integers where}\ n\geq1$

Answer: $\boxed{a_n=4(-3)^{n-1};\ \text{all integers where}\ n\geq1}$

4 0

3 years ago

Solve the equation 4s2+32s=60 by completing the square

lord [1]

Answer:

s = -4 ± √31

Step-by-step explanation:

Given 4 $s^{2}$ + 32s = 60