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2 years ago

In the passage, what event leads to a significant change in theodora’s circumstances?.

1 answer:

8 0

Based on the information given, it should be noted that in order to understand the event that leads to a significant change in Theodora’s circumstances, it is important to understand the plot in the story.

Your information is incomplete as you did not provide the passage. It should be noted that the plot is the sequence of events that enhances the principle of cause-and-effect in the story.

In this case, it is important to read and understand the story. Also, understand the theme and the plot. This is vital to know the event that leads to a significant change in Theodora’s circumstances?.

Learn more about plots on:

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Assume that when adults with smartphones are randomly selected, 57% use them in meetings or classes. If 10 adult smartphone user

blsea [12.9K]

The probability that at least 5 of them use their smartphones in meetings or classes will be 0.34.

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The number of combinations of 5 out of 10:

$^{10}C_4=\dfrac{10!}{5!(10-5)!}=\dfrac{10!}{5!\times 5!}\\\\\\^{10}C_4=\dfrac{10\times 9\times 8\times 7\times 6}{5\times 4\times 3\times 2}\\\\\\^{10}C_4=252$

The Success factor is:

57% = 0.57

The failure factor is:

(100 - 57)%= 43%= 0.43

So the Probability will be :

0.57⁵ x 0.43⁵ x 252 ≈ 0.34

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2 years ago

How does Supply and Demand affect needs and<br> wants and goods and<br> services

mina [271]

Answer:

Becuase if you supply and demand things there wont be enough needs and goods left

Explanation:

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3 years ago

The Boeing 757-200 ER airliner carries 200 passengers and has doors with a height of 72 in. Heights of men are normally distribu

Andreyy89

The probability that he can fit through the doorway without bending is 14.92%

<h3>How to find the p-value probability?</h3>

We are given;

Mean; μ = 69.5

Standard deviation; σ = 2.4

Sample mean; x' = 72

The standardized score is the value x decreased by the mean and then divided by the standard deviation. Thus;

z = (x' − μ)/σ

z = (72 − 69.5)/2.4

z = 1.04

Using p-value from z-score calculator gives us;

p-value = 0.1492 = 14.92%

Thus, the probability that he can fit through the doorway without bending is 14.92%

Complete Question is;

The Boeing 757-200 ER airliner carries 200 passengers and has doors with a height of 72 in. Heights of men are normally distributed with a mean of 69.5 in. and a standard deviation of 2.4 in. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending.

Read more about P-value from z-scores at; brainly.com/question/25638875

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2 years ago

A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin

Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

131.6 N/C

12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

$\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}$

Which gives;

$\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C$

$\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C$

Which gives;

$\vec{E}_1 = \mathbf{21.6 \, N/C \cdot \hat x + 28.8 \, N/C \hat y}$

$\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C$