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Alchen [17]
3 years ago
11

Solve the inequality.x/3-x-1/2≥1 a. x≤-3 b. x≥-3 c. x≤3 d. x≥3​

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

x ≤-9/4

Step-by-step explanation:

x/3-x-1/2≥1

Multiply each side by 6 to get rid of the fractions

6(x/3-x-1/2)≥1*6

2x -6x -3≥6

Combine like terms

-4x-3≥6

Add 3 to each side

-4x-3+3≥6+3

-4x ≥9

Divide each side by -4, remembering to flip the inequality

-4x/-4 ≤9/-4

x ≤-9/4

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Step-by-step explanation:

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Read 2 more answers
Which is greater 3/8 or 6/16
Semmy [17]

Answer:

they are the same

Step-by-step explanation:

They are the same

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7 0
3 years ago
12x+6x^2(3x-2)-8x^2-7x
Colt1911 [192]

Answer:

x⋅(2x+1)⋅(2x+3)⋅(3x−2)

Step-by-step explanation:

Equation at the end of step 1

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STEP

2

:

Equation at the end of step

2

:

 (((12 • (x4)) +  24x3) -  7x2) -  6x

STEP

3

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Equation at the end of step

3

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 (((22•3x4) +  24x3) -  7x2) -  6x

STEP

4

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STEP

5

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Pulling out like terms

5.1     Pull out like factors :

  12x4 + 16x3 - 7x2 - 6x  =

 x • (12x3 + 16x2 - 7x - 6)

Checking for a perfect cube :

5.2    12x3 + 16x2 - 7x - 6  is not a perfect cube

7 0
3 years ago
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