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Alchen [17]
3 years ago
11

Solve the inequality.x/3-x-1/2≥1 a. x≤-3 b. x≥-3 c. x≤3 d. x≥3​

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

x ≤-9/4

Step-by-step explanation:

x/3-x-1/2≥1

Multiply each side by 6 to get rid of the fractions

6(x/3-x-1/2)≥1*6

2x -6x -3≥6

Combine like terms

-4x-3≥6

Add 3 to each side

-4x-3+3≥6+3

-4x ≥9

Divide each side by -4, remembering to flip the inequality

-4x/-4 ≤9/-4

x ≤-9/4

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Solve the equation by the Quadratic Formula. Round to the nearest tenth, if necessary. Write your solutions from least to greate
Marat540 [252]

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = 10, b = -19 and c = 6.

Next step is to plug in these values in the above formula. Therefore,

So,

So,

Hope this helps you!

3 0
2 years ago
Write ACUTE, RIGHT, OBTUSE, STRAIGHT or REFLEX for each of the following: ( 5 marks)
soldier1979 [14.2K]

Answer:

a. obtuse angle

b. right angle

c. reflex angle

d. straight

e. acute angle

3 0
3 years ago
A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par
ElenaW [278]

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

-7x+3y=-21.5  

Convert it to the general form given below:

\rm y=mx+c

\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x or

\rm y = \frac{7}{3}x-\frac{21.5}{3}

m = \frac{7}{3}   (Slope of AB line)

For the slope(m') of the PQ line:

\rm m'=-\frac{1}{m}    ( because AB and PQ are perpendicular to each other)

\rm m' = -\frac{3}{7}

We know the:

\rm (y-y')=m'(x-x')

Where (x', y') = (7, 6), we get:

\rm (y-6)=-\frac{3}{7} (x-7)

\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63

\rm -1.5x-3.5y=-31.5   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0
2 years ago
Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.
aleksandrvk [35]

Answer:

The value of x is 3/2.

Step-by-step explanation:

Given data in the question:-

3^2^x=27

We have to find the value x.

Let 3^2^x=27 be eq(i).

Solving eq (i)

3^2^x=3^3

using the properties of the exponents we have

if aⁿ=aˣ

then n=x

2x=3\\x=3/2

Hence the answer is 3/2.

4 0
3 years ago
Need help for this one!
xeze [42]
(x+3 ; y-5)

If you have (-2 ; 3) that means x = -2 and y = 3 so:

(-2+3 ; 3-5) = (1 ; -2)
5 0
3 years ago
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