Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
has a melting point of - 39.76°C
and a boiling point of 388. 23°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C F - 32)
(
Express the range as an inequality and in interval notation
Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?
(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as
needed.)
and a boiling point of 388. 23°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C F - 32)
(
Express the range as an inequality and in interval notation
Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?
(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as
needed.)
1 answer:
You might be interested in
First of all, you can simplify the 4 at the numerator and the 14 at the denominator (they're both multiple of 2):
Now, rationalize a denominator means that you have to get rid of the square root, in order to have an integer denominator.
To do so, remember that you can always multiply any number by 1 without changing its value, and you can always think of 1 as a fraction where numerator and denominator are equal:
Use the distributive property to multiply −2 by x+1.
Combine 7x and −2x to get 5x.
Subtract 6x on both sides.
Combine 5x and −6x to get −x.
Add 2 to both sides.
Add 14 and 2 to get 16.
Multiply both sides by −1.