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ad-work [718]
2 years ago
9

Someone answer? Please

Physics
1 answer:
dexar [7]2 years ago
6 0
I don’t know ask your parents
You might be interested in
Pendulum clock. Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to con
levacccp [35]

Answer:

The time period for this pendulum is 1.68 seconds

Explanation:

Solution

Given that:

The length of the pendulum is measured from the axis of rotation to the center of mass of the bob of the pendulum

Now,

In this case, the length becomes:

L= 80 - 15+5

L = 70 cm

The time period = T = 2π √L/g

T = 2* 3.14 *√0.7/9.8

= 1.68 seconds

Note: Kindly find an attached work to the part of the solution of the given question

6 0
4 years ago
Examples for inertia
Lerok [7]

One's body movement to the side when a car makes a sharp turn.

Tightening of seat belts in a car when it stops quickly.

A ball rolling down a hill will continue to roll unless friction or another force stops it.

Men in space find it more difficult to stop moving because of a lack of gravity acting against them.

6 0
4 years ago
Please need help on this
Andrei [34K]

Q1 option 3

I hope it helps

3 0
3 years ago
A speedboat is moving at a constant speed, and the force propelling it forward is balanced by the force of the water pulling it
Kipish [7]
The correct answer is C: the speedboat's direction of motion will change. This is In fact, the new force of 500 N from the side of the boat is not balanced by any forces from the other side, and therefore this force will cause an acceleration in the direction of the force itself, which is not the same direction of motion. Therefore, the speedboat will acquire a movement on the lateral direction as well.
6 0
3 years ago
Read 2 more answers
A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
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