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Tresset [83]
3 years ago
6

while playing her guitar , karen plucks one string with increasin levels of force. what effect does this have on the sound produ

ced?
Physics
1 answer:
kirza4 [7]3 years ago
3 0
The sound will get louder.
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If you lift two loads up one story, how much work do you do compared to lifting just one load up one story?
Daniel [21]

Answer:a

Explanation:

We have to lift the load two loads up one story, so energy required is

let m be the mass of each load and h is the height of each story

Energy E_1=2\times m\times g\times \h

E_1=2mgh

Here energy gained is the potential energy which depends upon the datum(floor).

For lifting one load up one story

Energy required

E_2=mgh

thus E_2 is half of E_1

So option a is correct                                

6 0
3 years ago
A small bead of mass m is constrained to slide without friction inside a circular vertical hoop of radius r which rotates about
Stolb23 [73]

Answer:

Explanation:

The bead is moving on a vertical circular path so it must have a centripetal force towards the centre.

This force is equal to m v² / r

v is velocity of bead and r is radius of the circular path.

The vertical hoop is also rotating about a vertical axis passing through the centre at frequency f so the bead will experience a cetrifugal force due to rotation of the hoop. Its value is

m ω² r . Only at the point o degree and 180 degree , these forces are opposite to each other so at these points , the bead will be in equilibrium .

mv² / r = m ω² r

v² = ω² r²

v = ω r

= 2π f r

= 2 x 3.14 x 2 x 0.22

v = 2.76 m /s

For the bead to rise upto point θ = 90 degree , height achieved is radius R

required velocity = √ 2gR

= √ 2x 9.8x.22

= 2.076 m/s

This velocity is less than the velocity calculated earlier so the bead will be able to ride the required height.

v = 2.76 m/s

5 0
3 years ago
You are taking an image of a patient who is in extreme discomfort while participating in the CT scanning process. Which of the f
brilliants [131]

Answer:

Interpersonal skills

Explanation:

4 0
3 years ago
An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed
Tema [17]

Let the mass of 2500 kg car be m_1 and it's velocity be v_1 and the mass of 1500 kg car be m_2 and it's velocity be v_2 .

After the bumping the mass be M and it's velocity be V.

     By law of conservation of momentum we have

                   m_1v_1+m_2v_2 = MV

                    2500 * 5 + 1500 * 1=4000 * V

                    V = 14000/4000 = 7/2 = 3.5 m/s

So the velocity of the two-car train = 3.5 m/s

9 0
3 years ago
Tina's calculations of the tarantula found that the spider was able to cover 20 centimeters in five seconds what was the average
Sergeu [11.5K]
<span>(20 cm)/(5 sec) = (0.20 meters)/(5 seconds) 
</span>
8 0
4 years ago
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