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Vikentia [17]
3 years ago
14

For a research project, a student needs a solenoid that produces an interior magnetic field of 0.0300 T. She decides to use a cu

rrent of 1.00 A and a wire 0.500 mm in diameter. She winds the solenoid in layers on an insulating form 1.00 cm in diameter and 10.0 cm long. Determine the number of layers of wire needed. (Round your answer up to the nearest integer.)
Physics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

121m

Explanation:

Magnetic field = 0.03

Current = 1.00A

Diameter = 0.5

Length = 10vm

B = UoIN/Lcylinder * n

n = number of layer

n = 0.5x10^-3 x 0.03/4pi x 10^-7 x 1

= 0.0005x0.03/12.56x10^-7

= 11.94

~12

Average radius

= 0.008

Length of wire = 2x3.13x0.008x12x200

= 120.6m

= 121m

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Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic fie
Sliva [168]

Answer:

Please find the answer in the explanation

Explanation:

Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic field at locations other than the central axis.

What happens as you move away from the center axis toward the coil? The direction of the magnetic compass needle will move in an opposite direction since the direction of the induced voltage is reversed.

What happens above the coil?

the needle on the magnetic compass will be deflected. Since compasses work by pointing along magnetic field lines

Outside the coil? The magnetic compass needle will experience no deflection. Since there is no induced voltage or current.

Below the coil?

The needle will move in an opposite direction.

3 0
3 years ago
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm
Colt1911 [192]
The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
E=-  \frac{13.6}{n^2} [eV]
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2}  )[eV]=3.02 eV
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this \Delta E. Converting it into Joule,
\Delta E=3.02 eV=4.84 \cdot 10^{-19}J
The energy of the photon is
E=hf
where h is the Planck constant while f is its frequency. Writing \Delta E=hf, we can write the frequency f of the photon:
f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz

The photon travels at the speed of light, c=3 \cdot 10^8 m/s, so its wavelength is
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.
4 0
4 years ago
Read 2 more answers
A car travels 70 km in two hours 104 km in the next 1.5 hours and then 79 km in two hours before reaching its destination what w
stiks02 [169]

Average speed = (total distance) / (total time)

Total distance = (70km + 104km + 79km) = 253 km

Total time = (2hr + 1.5hr + 2hr) = 5.5 hrs

Average speed = (253 km) / (5.5 hrs)

<em>Average speed = 46 km/hr</em>

4 0
4 years ago
The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.
oksano4ka [1.4K]

Answer:

i = 2.84 \times 10^{-3} A

Explanation:

As we know that current density is ratio of current and area of the crossection

now we have

J = \frac{di}{dA}

so the current through the wire is given as

i = \int J dA

now we have

i = \int_{0.921R}^R J dA

here we have

J = (3.25 \times 10^8)r^2

now plug in the values in above equation

i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr

now we have

i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr

i = (2.04 \times 10^9) \frac{r^4}{4}

now plug in both limits as mentioned

i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})

i = (2.04\times 10^9)(0.07 R^4)

here R = 2.11 mm

i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)

i = 2.84 \times 10^{-3} A

8 0
3 years ago
a net force of 1,800 N is applied to a boat causing it to accelerate at 1.5 m/s^2. what is the mass of the boat?
Xelga [282]

Answer:

<h3>The answer is 1200 kg</h3>

Explanation:

The mass of an object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{1800}{1.5}  \\

We have the final answer as

<h3>1200 kg</h3>

Hope this helps you

7 0
4 years ago
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