The width of a rectangle is a whole number of centimetres. a The length of the rectangle is 9 cm longer than its width. The peri
meter of the rectangle is less than 200 cm. Find the greatest possible width of the rectangle.
1 answer:
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Your equation is a linear equation because it has a constant, and it has variables. And it does not have something like x^2.
However, if your question wants it in slope-intercept format, which is y=mx+b
Then:
3x-4y = 4
We can add 4y to both sides
3x = 4+4y
Subtract 4 from both sides
3x-4 = 4y
Then we divide by 4
So 3x-4y=4 in slope-intercept format would be
However, if your question wants it in slope-intercept format, which is y=mx+b
Then:
3x-4y = 4
We can add 4y to both sides
3x = 4+4y
Subtract 4 from both sides
3x-4 = 4y
Then we divide by 4
So 3x-4y=4 in slope-intercept format would be
