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2 years ago

Show work! my teacher told me this was wrong, what's the correct answer?

Mathematics

1 answer:

Studentka2010 [4]2 years ago

7 0

Answer:

it is Ahmed shoevked more your calculations are wrong

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The abc store sold 142 c.d.'s at $10.50 each, 80 audio tapes which cost $8.00 a price, 30 videos priced at $15.00 each and $150

Lina20 [59]

Answer:

2731

Step-by-step explanation:

Mark me brainiest

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3 years ago

The old man looked out, then beckoned frantically for Greg to follow him. For a moment Greg couldn’t move. Then he found himself

Effectus [21]

Answer:

i think its A?

Step-by-step explanation:

because he is warning greg?

4 0

2 years ago

Read 2 more answers

-5+2(10b-2)=31 need help thanks!

Contact [7]

Answer:

$\Large \boxed{b=2}$

Step-by-step explanation:

-5+2(10b-2)=31

Expand brackets.

-5+20b-4=31

-9+20b=31

Add 9 on both sides.

20b=40

Divide both sides by 20

b=2

8 0

3 years ago

Read 2 more answers

A friend makes three pancakes for breakfast. One of the pancakes is burned on both sides, one is burned on only one side, and th

Semmy [17]

Answer:

50%

Step-by-step explanation:

Given that one side of the pancake is burned. The pancake you were served cannot be the one that is not burned on either side. Therefore, you were either served the pancake burned on both sides, or the pancake that was only burned in one side. Thus, there is a 50% percent chance that the other side is also burned.

7 0

3 years ago

For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

3 years ago

Show work! my teacher told me this was wrong, what's the correct answer?​

Show work! my teacher told me this was wrong, what's the correct answer?