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3 years ago

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Help me pls somebody

1 answer:

Nataliya [291]3 years ago

4 0

Answer:

Its A

Step-by-step explanation:

i know

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What is 67 Divded by 46,514

Gnesinka [82]

Answer : <span>0.00144042653

67 </span>÷ 46,514 = <span>0.00144042653

Hope this Helps ._.</span>

5 0

3 years ago

Read 2 more answers

A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate

Shkiper50 [21]

The amount of salt in the tank changes with rate according to

$Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)$

$\implies Q'+\dfrac Q{300+3t}=4$

which is a linear ODE in $Q(t)$ . Multiplying both sides by $(300+3t)^{1/3}$ gives

$(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}$

so that the left side condenses into the derivative of a product,

$\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}$

Integrate both sides and solve for $Q(t)$ to get

$(300+3t)^{1/3}Q=(300+3t)^{4/3}+C$

$\implies Q(t)=300+3t+C(300+3t)^{-1/3}$

Given that $Q(0)=100$ , we find

$100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}$

and we get the particular solution

$Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}$

$\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}$

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3 years ago

Which operation would you do first? 2 · (15 - 2) ÷ 5

ki77a [65]

You would have to do 15 - 2 because according to PEMDAS you do parentheses first and you would do the multiplication and division

3 0

4 years ago

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4 pounds of grapes cost $11.52. what is the unit rate?

Zepler [3.9K]

Answer: 2.88/1

Step-by-step explanation:

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3 years ago

Evaluate the function f(x) = 2x^2 -3x + 5 for the input value of -3

tigry1 [53]

Answer:

$f(-3) = 32$

Step-by-step explanation:

<u>Step 1: Set x to -3</u>

<u /> $f(x) = 2x^2 - 3x + 5$

$f(-3) = 2(-3)^2 - 3(-3) + 5$

$f(-3) = 2(9) + 9 + 5$

$f(-3) = 18 + 9 + 5\\$

$f(-3) = 32$

Answer: $f(-3) = 32$

3 0

3 years ago