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RideAnS [48]
2 years ago
10

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Mathematics
2 answers:
Dimas [21]2 years ago
8 0
143 / 6x+12 = 132 / 72
143 / 6x+12 = 11 / 6

crossmultiply:
66x + 132 = 858
66x = 726
x = 11
FromTheMoon [43]2 years ago
8 0

Answer:

\frac{vw}{gf}  =  \frac{uv}{hg}

\frac{72}{132}  =  \frac{6x + 12}{143}

\frac{6}{11}  =  \frac{6x + 12}{143}

Now we cross multiply

6×143=11(6x+12)

858=66x+132

858-132=66x

726=66x

x=11

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Solve the liner equation <br> 17-x=1/2(15)+6
Genrish500 [490]

Answer:

x = 3.5

Step-by-step explanation:

15(1/2) = 7.5

7.5+6 =13.5

subtract 17 and divide by -1 to isolate x 13.5-17/-1

x = 3.5

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3 years ago
David drove 1,092 miles in 7 days
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Find x. Round your answer to the nearest tenth. <br><br> ______________
liubo4ka [24]

Answer:

Step-by-step expThis is the concept of trigonometry, the value of x will be calculated as follows;

sin theta=[opposite]/[hypotenuse]

theta=x

opposite=16 units

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thus;

sin x=16/21

hence;

x=arcsin(16/21)

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7 0
3 years ago
In a two-digit number, the first digit is 5 less than the second digit. The number itself is three times the sum of its digits.
nika2105 [10]

Answer:

Step-by-step explanation:

27

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6 0
4 years ago
What is 5x+4y=-14, 3x+6y=6 in matrix
yarga [219]

Answer:

\left[\begin{array}{ccc}5&4\\3&6\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}-14\\6\end{array}\right] is the required matrix form.

Step-by-step explanation:

Here, the given system of equation is:

5 x + 4 y = -14,

3 x + 6 y = 6

In a system of equation, the matrix for is given as

AX = b

Here, A  = Co-efficient Matrix, X =  Variable Matrix and B = Constant Matrix

Considering the given system:

Co-efficient Matrix(A)  = \left[\begin{array}{ccc}5&4\\3&6\end{array}\right]

Variable Matrix(X) = \left[\begin{array}{ccc}x\\y\end{array}\right]

Constant Matrix(b)   =\left[\begin{array}{ccc}-14\\6\end{array}\right]

Hence, the combined matrix form  of AX = b is

\left[\begin{array}{ccc}5&4\\3&6\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}-14\\6\end{array}\right]

4 0
3 years ago
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