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2 years ago

Please help me somebody!!! I really struggle with this in math class!

Mathematics

1 answer:

Tresset [83]2 years ago

4 0

Answer:

$y - 9 = -\frac{4}{3}(x - 3)$

Step-by-step explanation:

Given the points (3, 9) and (9, 1), we must first solve for the slope of the line before proceeding with writing the point-slope form.

In order to solve for the slope (m ), use the following formula:

m = (y₂ - y₁)/(x₂ - x₁)

Let (x₁, y₁) = (3, 9)

(x₂, y₂) = (9, 1)

Substitute these values into the given formula:

m = (y₂ - y₁)/(x₂ - x₁)

m = (1 - 9)/(9 - 3)

$m = \frac{-8}{6} = \frac{-4}{3}$

Therefore, the slope of the line, m = -4/3.

Next, using the slope, m = -4/3, and one of the given points, (x₁, y₁) = (3, 9), substitute these values into the following point-slope form:

y - y₁ = m(x - x₁)

$y - 9 = -\frac{4}{3}(x - 3)$ ⇒ This is the point-slope form.

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Write a series of rigid motions that transform pentagon ABCDE to pentagon A′B′C′D′E′

worty [1.4K]

Answer:

We need the following three rigid motions:

i) Reflection around y-axis, ii) Translation three units in the -y direction, iii) Translation four units in the -x direction.

Step-by-step explanation:

We need to perform three operations on pentagon ABCDE to create pentagon A'B'C'D'E':

i) Reflection around y-axis:

$(x',y') = (-x,y)$ (Eq. 1)

ii) Translation three units in the -y direction:

$(x'',y'') = (x', y'-3)$ (Eq. 2)

iii) Translation four units in the -x direction:

$(x''',y''') = (x''-4, y'')$ (Eq. 3)

We proceed to proof the effectiveness of operations defined above by testing point D:

1) $D(x,y) = (-1, 4)$ Given.

2) $(x',y') = (1,4)$ By (Eq. 1)

3) $(x'',y'') = (1, 1)$ By (Eq. 2)

4) $D'(x,y) = (-3,1)$ By (Eq. 3)/Result

7 0

2 years ago

The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."

Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

$csc(\theta)=\frac{1}{sin(\theta)}$

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

6 0

3 years ago

It's possible to build a triangle with side lengths of 3, 3, and 9. O A. True O B. False

Svetllana [295]

Add up 3+3=6, number has to be bigger than 9 so the answer is false.

5 0

2 years ago

Find f ∘ g f∘g and g ∘ f g∘f. f ( x ) = x 2 / 3 , g ( x ) = x 9 f(x)=x2/3, g(x)=x9 (a) f ∘ g f∘g (b) g ∘ f g∘f Find the domain o

faltersainse [42]

I don’t know it’s soooo long:)

8 0

3 years ago

The estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is

mixas84 [53]

Answer: The equation that represents the give situation is, y = 0.75 x + 12

Step-by-step explanation:

Here, x represents the number of batteries the child bought and y represents the total cost.

Since, the cost of one batteries = $ 0.75

⇒ The cost of x batteries = 0.75 x

The cost of one toy = $ 12

Hence, the total cost = The cost of one toy + The cost of x batteries

= y = 0.75 x + 12

Which is the required equation that represents the given situation.

6 0

3 years ago

Read 2 more answers