Question

6, -12, 24, 8th term of geometric sequence

Answer 1

Answer:

a₈ = - 768

Step-by-step explanation:

The nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = $\frac{a_{2} }{a_{1} }$ = $\frac{-12}{6}$ = - 2 , then

a₈ = 6 × $-2)^{7}$ = - 6 × - 128 = - 768