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3 years ago

6, -12, 24, 8th term of geometric sequence

Mathematics

1 answer:

nordsb [41]3 years ago

5 0

Answer:

a₈ = - 768

Step-by-step explanation:

The nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = $\frac{a_{2} }{a_{1} }$ = $\frac{-12}{6}$ = - 2 , then

a₈ = 6 × $-2)^{7}$ = - 6 × - 128 = - 768

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Artist 52 [7]

Answer:

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3 years ago

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AleksAgata [21]

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3 years ago

Given that segment AB is tangent to the circle shown in the diagram centered at point C, determine the value of x

Ulleksa [173]

Answer:

Step-by-step explanation:

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given (as seen from the diagram)

x, hypotenuse= ?

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$hyp^2= opp^2+adj^2\\\\hpy=\sqrt{opp^2+adj^2}$

Substituting our given data and solving for hpy we have

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3 years ago

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Firdavs [7]

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Step-by-step explanation:

<em>Let's calculate the acute angle at the base of the triangle:</em>

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3 years ago

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luda_lava [24]

Answer:

It is a right angled triangle.

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2 years ago