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KiRa [710]
2 years ago
15

6, -12, 24, 8th term of geometric sequence

Mathematics
1 answer:
nordsb [41]2 years ago
5 0

Answer:

a₈ = - 768

Step-by-step explanation:

The nth term of a geometric sequence is

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = \frac{a_{2} }{a_{1} } = \frac{-12}{6} = - 2 , then

a₈ = 6 × -2)^{7} = - 6 × - 128 = - 768

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