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mrs_skeptik [129]
2 years ago
12

PLEASE HELP OMG PLEASE

Mathematics
1 answer:
gladu [14]2 years ago
3 0

Answer:

Step-by-step explanation:

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You flip a coin three times.What is. the probability of getting at least 1 head? A.1/8
astra-53 [7]
The answer is B 3/8
4 0
4 years ago
Can someone help me Find the value of X
Aleksandr [31]

Answer: x=4

Step-by-step explanation:

similar triangle so corresponding parts are similar

\frac{5}{10} = \frac{2x-1}{14}

cross multiply

70 = 20x-10

80 = 20x

x = 4

3 0
3 years ago
John, Sally, and Natalie would all like to save some money. John decides that it would be best to save money in a jar in his clo
Radda [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) y=100x+300

Part 3) \$12,300

Part 4) Is a exponential growth function

Part 5) A=6,000(1.07)^{t}  

Part 6) \$11,802.91  

Part 7) Is a exponential growth function

Part 8) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}  

Part 9)  \$13,591.41

Part 10) Natalie has the most money after 10 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

y=100x+300

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10 years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1  

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}  

A=6,000(1.07)^{t}  

therefore

Is a exponential growth function

Part 5) Write the model equation for Sally’s situation

A=6,000(1.07)^{t}  

see the Part 4)

Part 6) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91  

Part 7) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10  

substitute in the formula above

A=5,000(e)^{0.10t}  

Applying property of exponents

A=5,000(1.1052)^{t}  

therefore

Is a exponential growth function

Part 8) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 7)

Part 9) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 10) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

4 0
4 years ago
Read 2 more answers
Which property does this show? 4(3 - x) = 12 - 4x
leva [86]

Answer:

Distributive property

Step-by-step explanation:

when you distribute the left sid dit equals the right

3 0
3 years ago
A construction company is building a new parking garage and is charging the following rates: $5000 a month for the first 3 month
Elena L [17]

Answer:

C(t) = 5t for 0 < t ≤ 3

C(t) = (8t-9) for 3 < t ≤ 6

C(t) = 44 for 6 < t ≤ 10

C is given in thousands of dollars and t is given in months.

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Step-by-step explanation:

We will do a piecewise analysis for this cost function.

How to obtain the total cost changes with each time interval.

In the first 3 months,

C(t) = 5t for 0 < t ≤ 3

Note that C is given in thousands of dollars

In the next 3 months,

C(t) = (8t-9) for 3 < t ≤ 6

- Here, it gets a little complex, we use the upper limit of the previous interval and the lower limit of this new interval to get the constant to be subtracted from the normal 8t that characterizes this interval.

8(3) = 24

5(3) = 15

constant = 24 - 15 = 9

In the last 4 months,

C(t) = 44 for 6 < t ≤ 10

- For the last four months, it is a single sum of $5000 plus the [8(6) - 9] from the previous inteval

C = [8(6) - 9] + 5 = 39 + 5 = 44

So, the cost of parking, tracked month after month gives

T | Cost (in thousands of dollars)

1 | 5

2 | 10

3 | 15

4 | 23

5 | 31

6 | 39

7 | 44

8 | 44

9 | 44

10 | 44

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Hope this Helps!!!

8 0
3 years ago
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