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2 years ago

HELP IM IN DESPERATE NEED!!! What is the solution to this system of equations?

Mathematics

1 answer:

Paladinen [302]2 years ago

6 0

[Given]

{ x + y = 6

{ x = y + 4

[Plug-in our x value & solve]

[Given] x + y = 6

[ Plug-in] (y + 4) + y = 6

[Distribute] y + 4 + y = 6

[Combine like terms] 2y + 4 = 6

[Subtract 4 from both sides] 2y = 2

[Divide both sides by 2] y = 1

[Answer]

Third option - (5, 1)

-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly

Have a nice day!

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- Heather

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Suppose X, Y, and Z are random variables with the joint density function,

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$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

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$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

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C = 0.01

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