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Reika [66]
2 years ago
12

One cookie and two brownies cost the same as two cookies and one brownie. One cookie and one brownie together cost $1. What is t

he cost, in cents, of one cookie?
Mathematics
2 answers:
leonid [27]2 years ago
8 0
Answer : Cookie is 50 cents.
Step by step explanation :
Cookie = x and brownie = y
Equation : x + 2y = 2x + y
Subtract y on both sides.
X + y = 2x
Since x + y equals 1, plug that into the equation.
1 = 2x
X = 0.5, or 50 cents
One cookie costs 50 cents. Please mark brainliest if possible ;)
adoni [48]2 years ago
6 0

Answer:

50 cents

Step-by-step explanation:

Let's set up a system of equations. Let x be a cookie and y be a brownie then...

x+2y=2x+y

x+y=1

We can solve this using substitution

x=1-y

1-y+2y=2(1-y)+y

1+y=2-2y+y

1+y=2-y

-1=-2y

y=1/2

One brownie costs 50 cents and one cookie costs...

x+1/2=1

x=1/2

One cookie costs 50 cents

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What is the p-value? -- Researcher Jessie is studying how the fear of going to the dentist affects an adult's actual number of v
Vesnalui [34]

Answer:

Two, one for the 14 responses (number of visits) by the adults who fear going to the dentist and one for the 31 responses (number of visits) by the adults who do not fear going to the dentist.

Step-by-step explanation:

Hello!

1)

You want to test if the average visits to the dentist of people who fear to visit it are greater than the average visits of people that don't fear it.

In this case, the statistic to use is a pooled Student t-test. The reason I've to choose this test is that one of your sample sizes is small (n₁= 14) and the t-test is more accurate for small samples. Even if the second sample is greater than 30, if both variables are normally distributed, the pooled t-test is the one to use.

H₀: μ₁ = μ₂

H₁: μ₁ > μ₂

α: 0.10

t=<u> (X₁[bar]-X₂[bar]) - (μ₁ - μ₂)</u> ~ t_{n₁+n₂-2}

        Sₐ√(1/n₁+1/n₂)

Where

X₁[bar] and X₂[bar] are the sample means of both groups

Sₐ is the pooled standard deviation

This is a one-tailed test, you will reject the null hypothesis to big numbers of t. Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis), and in this case, is also one-tailed.

P(t_{n₁+n₂-2} ≥ t_{H0}) = 1 - P(t_{n₁+n₂-2} < t_{H0})

Where t_{H0} is the value of the calculated statistic.

Since you didn't copy the data of both samples, I cannot calculate it.

2)

Well there was one sample taken and separated in two following the criteria "fears the dentist" and "doesn't fear the dentist" making two different samples, so this is a test for two independent samples. To check if both variables are normally distributed you need to make two QQplots.

I hope it helps!

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Step-by-step explanation:

If u want the help to simplify it to a fraction use Y Homework and it will solve it for u in a sec

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