suppose that we attach velcro® to the non-magnetic ends of the two carts in the video and remove the mass bars, so that both car
1 answer:
The momentum conservation allows to find the final speed of the cars together are:
- If the second car is stopped, the final speed is: v = vo / 2
- If the second car moves towards the first, the final speed is: v = 0
The momentum is defined by the product of the mass and the speed of the body.
p = m v
Where the bold letters indicate vector, p is the moment, m is the mass and v the velocity.
If we define the system as formed by the two bodies, the forces during the collision are internal and the momentum is preserved, let's find the moment in two instants.
Initial instant. Before crash.
p₀ = m v₀₀₀+ m v₀₂
Final moment. After the crash.
The moment is preserved.
We have two cases:
- That the second car is initially stopped, therefore the speed is zero
v = v₀ / 2
- That the second car move towards the first with velocity v₀₂ = - vo
v = 0
In conclusion using the momentum conservation we can find the final velocity of the cars together are:
- If the second car is stopped, The final speed is: v = vo / 2
- If the second car moves towards the first, the final speed is: v = 0
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Under the action of this force, the electron moves by:
And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:
(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
Where Uf and Ui are the final and initial potential energy of the electron.
(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
(1)
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as
and by using the mass of the electron me, we can find the value of the final velocity of the electron:
Under the action of this force, the electron moves by:
And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:
(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
Where Uf and Ui are the final and initial potential energy of the electron.
(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as
and by using the mass of the electron me, we can find the value of the final velocity of the electron: