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notsponge [240]
3 years ago
10

A ray of laser light travels through air and enters an unknown material. The laser enters the material at an angle of 36 degrees

to the normal. The refracted angle is 27.5 degrees. If the index of refraction of air is n = 1.00, what is the index of refraction of the unknown material?
Physics
1 answer:
V125BC [204]3 years ago
3 0

Answer:1.27

Explanation:

Given

incident angle i=36^{\circ}

refracted angle r=27.5^{\circ}

Suppose n_2 is the refractive index of material then using Snell's law we  can write

n_1\sin i=n_2\sin r

where n_1=refractive index of air

1\times \sin (36)=n_2\times \sin (27.5)

n_2=\dfrac{0.5877}{0.4617}

n_2=1.27

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Answer:

a)   v_average = 11 m / s, b)  t = 0.0627 s

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, d)   F / W = 35.8

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a) truck speed can be found with kinematics

         v² = v₀² - 2 a x

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           a = v₀² / 2x

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The average speed is

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b) The average time

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          t = v₀ / a

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