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abruzzese [7]
2 years ago
13

The Planet Venus is surrounded by a thick layer of gases. In fact the atmospheric preassure on Venus is over 90 times grater tha

n the atmospheric preassure on Earth. Wcich statements are true about boiling water on Venus? Choose the TWO STATEMENTS that aply.
A. Water will boil at a higher temperature on Venus than on Earth.
B. Water will boil at a lower temperature on Venus than on Earth.
C. The temperature of the water will remain constant as it boils.
D. The temperature will increase as it boils.
Chemistry
1 answer:
SCORPION-xisa [38]2 years ago
7 0
B. water will boil at a lower temperature on Venus than on Earth.
Explanation:
Because temperature and pressure are directly proportional... increase in pressure will increase in the atmospheric temperature.... Venus has higher pressure than earth that also means it has higher atmospheric temperature and as the temperature is already high the water will require lesser heat to boil
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What are the elements in group 3-12 called
Wittaler [7]

Answer:

Transition Metals

Explanation:

The elements in groups 3-12 are called Transition Metals. These groups contain metals that usually form multiple cations. All other groups on the table (1, 2, 13-18) are called Main Group Elements.

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HElP PLS!! 20 points Which statement best describes a characteristic unique to renewable resources?
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renewable resources are abundant???

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Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
insens350 [35]
Given:
Iron, 125 grams T
1 = 23.5 degrees Celsius, T2 = 78 degrees Celsius.  

Required:
Heat produced in kilojoules  

Solution:
The molar mass of iron is 55.8 grams per mole. SO we need to change the given mass of iron into moles.  
 
Number of moles of iron = 125 g/(55.8 g/mol) = 2.24 moles  
<span>
Q (heat) = nRT = nR(T2 = T1)</span>
Q (heat) = 2.24 moles (8.314 Joules per mol degrees Celsius) (78.0 degrees Celsius – 23.5 degrees Celsius)
<u>Q (heat) = 1014.97 Joules or 1.015 kilojoules</u> <span>This is the amount of heat produced in warming 125 g f iron.</span>
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Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o
stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of butane

\text{Number of moles}=\frac{5.2g}{58.12g/mol}=0.09moles

b) moles of oxygen

\text{Number of moles}=\frac{32.6g}{32g/mol}=1.02moles

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

According to stoichiometry :

2 moles of butane require 13 moles of O_2

Thus 0.09 moles of butane will require =\frac{13}{2}\times 0.09=0.585moles  of O_2

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0
3 years ago
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