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2 years ago

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When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of

AlCl3?
Al (s) + ZnCl2 (aq) yields Zn (s) + AlCl3 (aq)

1 answer:

jasenka [17]2 years ago

4 0

2Al + 3ZnCl₂ ----> 3Zn + 2AlCl₃

What is the coefficient in front of AlCl₃? ==>> 2

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

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2 years ago

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Chemicals A and B react according to the equation A + B → C. How will the concentrations of each component of the reaction chang

Firlakuza [10]

The concentration of a and b will decrease while c will increase provided all other physical quantities are kept constant in the reaction

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2 years ago

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Though Neon is a relatively small atom with a relatively high nuclear charge, it is difficult to add an electron to a neon atom.

Feliz [49]

Answer:

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Explanation:

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2 years ago

Ergosterol, a precursor of vitamin D, has δmax = 282 nm and molar absorptivity ε = 11,900 M-1cm-1. What is the concentration of

meriva

Answer:

3.6 × 10⁻⁵ M

Explanation:

Ergosterol has a maximum absorbance at λ = 282 nm. The absorbance of an analyte is related to its concentration through the Beer-Lambert's law.

A = ε × <em>l</em> × c

where,

A: absorbance

ε: molar absorptivity

<em>l</em>: optical path length

c; molar concentration

c = A / ε × <em>l </em>= 0.43 / (11,900 M⁻¹cm⁻¹) × 1.00 cm = 3.6 × 10⁻⁵ M

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2 years ago

Ignore the answer I have selected but please help!! Ty in advance, also please explain

weeeeeb [17]

Answer:

Iodine is most reactive because it is very close to having a "full shell" which is 8 electrons so they are "eager" to gain the last electron to became balanced, so that makes it the most reactive. Hope that helps:)

Explanation:

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2 years ago