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CaHeK987 [17]
3 years ago
9

Quinine is a natural product extracted from the bark of the cinchona tree, which is native to South America. Quinine is used as

an antimalarial agent. When 3.28 g of quinine is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 8.43 °
c. The freezing point and Kf constant for cyclohexane can be found here.
Calculate the molar mass of quinine.
Chemistry
1 answer:
evablogger [386]3 years ago
5 0
For the answer to the question above, <span>The formula for freezing point depression is </span>
<span>ΔTf = mkfi </span>

<span>kf is the freezing point constant </span>
<span>i is the Van't Hoff factor which in this case is 1 </span>
<span>m is molality (moles of solute/kg of solvent) </span>
<span>ΔTf is temperature change </span>

<span>ΔTf is 2.17 °C, the molality is the amount of solute Quinine </span>
<span>in the solvent cyclohexane. We cannot calculate moles therefore we need to substitute moles with g/mm. </span>

<span>moles = g/mm so molality=(g/mm)/kg </span>
<span>molality = (0.845/mm)/0.025 = 33.8/mm </span>

<span>2.17 = 33.8/mm(20.8) rearrange </span>

<span>mm = (33.8/2.17)(20.8) = 324g/mol</span>
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Solution :

It is given that :

The formula of the compound = $XBr_3$

And that 4.70 g of the sample contains $4.834 \times 10^{-2}$ mol of Br.

It means that :

1 mol of $XBr_3$ contains = 3 mol of Br

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$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

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The given mass is = 4.700 g

Therefore, the $\text{molar mass}$ of $XBr_3$  $=\frac{\text{mass}}{\text{mol}}$

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So $\text{molar mass}$ of $XBr_3$ = $\text{molar mass}$ of X + 3 x $\text{molar mass}$ of Br

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