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CaHeK987 [17]
3 years ago
9

Quinine is a natural product extracted from the bark of the cinchona tree, which is native to South America. Quinine is used as

an antimalarial agent. When 3.28 g of quinine is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 8.43 °
c. The freezing point and Kf constant for cyclohexane can be found here.
Calculate the molar mass of quinine.
Chemistry
1 answer:
evablogger [386]3 years ago
5 0
For the answer to the question above, <span>The formula for freezing point depression is </span>
<span>ΔTf = mkfi </span>

<span>kf is the freezing point constant </span>
<span>i is the Van't Hoff factor which in this case is 1 </span>
<span>m is molality (moles of solute/kg of solvent) </span>
<span>ΔTf is temperature change </span>

<span>ΔTf is 2.17 °C, the molality is the amount of solute Quinine </span>
<span>in the solvent cyclohexane. We cannot calculate moles therefore we need to substitute moles with g/mm. </span>

<span>moles = g/mm so molality=(g/mm)/kg </span>
<span>molality = (0.845/mm)/0.025 = 33.8/mm </span>

<span>2.17 = 33.8/mm(20.8) rearrange </span>

<span>mm = (33.8/2.17)(20.8) = 324g/mol</span>
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What mass of Ba3(PO4)2 is contained in 1575 mL of a 0.35 M solution of Ba3(PO4)2?
irina [24]

Answer:

= 331.81 g

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

Therefore;

Moles = Molarity ×Volume in liters

          = 0.35 M × 1.575 L

          = 0.55125 Moles

But; Molar mass of Ba3(PO4)2 is 601.93 g/mol

Thus;

Mass = 0.55125 moles × 601.93 g/mol

         <u>= 331.81 g</u>

3 0
3 years ago
Which elements did you include in your question?
SIZIF [17.4K]

Answer:

It should be all of them

Explanation:

It’s because it was in your question you wrote out

3 0
3 years ago
An acid sample of an unknown concentration is contained in a erlenmeyer flask. Which technique below would be best suited to ana
Ivenika [448]

Answer:

Titration

Explanation:

The best technique which can be used to determine the number of moles of the HCl in the sample is titration.

The given amount of HCl solution must be titrated with known concentration of the base like NaOH.

The volume of NaOH required must be noted also.

According to the reaction,

NaOH+HCl\rightarrow NaCl+H_2O

At equivalence point

Moles of HCl = Moles of NaOH

Considering:-

Moles of HCl=Molarity_{NaOH}\times Volume_{NaOH}

Thus, in this way, moles of HCl can be determined.

4 0
3 years ago
How many moles are there in 2.75L of a 2.0M solution
gtnhenbr [62]
5.5 moles
2.0=x/2.75
2.0*2.75= x/2.75 (2.75)
5.5=x
7 0
3 years ago
If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?
GarryVolchara [31]

Answer:

            385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

                                       2 H₂  +  O₂    →   2 H₂O

According to Equation,

        4.032 g ( 2 mol) H₂ reacts to produce  =  36.03 g (2 mol) of H₂O

So,

        48.6 g H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                     X =  (48.6 g × 36.03 g) ÷ 4.032 g

                     X  =  434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

                    36.03 g (2 mol) H₂O is produced by  =  31.998 g (1 mol) of O₂

So,

                434.29 g of H₂O will be produced by  =  X g of O₂

Solving for X,

                     X =  (434.29 g × 31.998 g) ÷ 36.03 g

                    X  =  385.69 g of O₂

8 0
3 years ago
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