Answer:
= 331.81 g
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
Therefore;
Moles = Molarity ×Volume in liters
= 0.35 M × 1.575 L
= 0.55125 Moles
But; Molar mass of Ba3(PO4)2 is 601.93 g/mol
Thus;
Mass = 0.55125 moles × 601.93 g/mol
<u>= 331.81 g</u>
Answer:
It should be all of them
Explanation:
It’s because it was in your question you wrote out
Answer:
Titration
Explanation:
The best technique which can be used to determine the number of moles of the HCl in the sample is titration.
The given amount of HCl solution must be titrated with known concentration of the base like NaOH.
The volume of NaOH required must be noted also.
According to the reaction,

At equivalence point
Moles of
= Moles of 
Considering:-
Moles of 
Thus, in this way, moles of HCl can be determined.
5.5 moles
2.0=x/2.75
2.0*2.75= x/2.75 (2.75)
5.5=x
Answer:
385.69 g of O₂
Solution:
The Balance Chemical equation for said reaction is as follow;
2 H₂ + O₂ → 2 H₂O
According to Equation,
4.032 g ( 2 mol) H₂ reacts to produce = 36.03 g (2 mol) of H₂O
So,
48.6 g H₂ on reaction will produce = X g of H₂O
Solving for X,
X = (48.6 g × 36.03 g) ÷ 4.032 g
X = 434.29 g of H₂O
It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).
So, According to Equation,
36.03 g (2 mol) H₂O is produced by = 31.998 g (1 mol) of O₂
So,
434.29 g of H₂O will be produced by = X g of O₂
Solving for X,
X = (434.29 g × 31.998 g) ÷ 36.03 g
X = 385.69 g of O₂