Answer:
According to my research A molecule is two or more atoms held together by covalent bonds. An atom is the smallest part of an element. ... A sodium atom has one outer electron, and a carbon atom has four outer electrons.
Explanation:
Answer:
is an aqueous reactant
is a liquid product
is a gaseous product
Explanation:
⇔ 
Hydrogen carbonate dissocates to form carbon dioxide and water. The acid (hydrogen carbonate) is in aqueous form and it dissociates to water (liquid) and carbon dioxide (a gas). It is also seen that the hydrogen carbonate is on the reactant side and it dissociates to produce water and carbon dioxide.
W<u> is an aqueous reactant</u> (a reactant undergoes changes in a chemical reaction
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<u> is a liquid product</u> (product refers to the species produced from chemical reaction)
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<u> is a gaseous product</u>
Answer:
Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)
Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)
Explanation:
When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.
That a reaction quotient always assumes the same value at equilibrium can be expressed as:
Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…
This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.
Answer:
opción c es la respuesta correcta espero que te ayude
With reference to radioactive material, half-life is the time required to 50% depletion of initial amount of material.
Given: Initial amount of radioactive material = 40 g
Half life = 4 days.
Therefore, After 4 days, amount of compound left = 40/2 = 20 g
After 8 days, i.e 2 half-life, amount of compound left = 20/2 = 10 g
Finally after 12 days, i.e. 3 half-life, amount of compound left = 10/2 = 5 g
Thus, 5 <span>grams will remain after 12 days</span>
