Answer:
463833
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Medium
Solution
verified
Verified by Toppr
In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
The answer for (1/3)*120 is 40
We can then write an equation representing this problem as:
e−1.5mi=5.25mi
Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:
e−1.5mi+1.5mi=5.25mi+1.5mi
e−0=6.75mi
e=6.75mi
The plane's starting elevation was 6.75 miles
Hope this helps!
Answer: 36.9
Step-by-step explanation:
For this question you have to find out whether you are using Sin, Cos or Tan.
To work out which one you are using you can use SOH CAH TOA to help you.
SOH- The 'S' is for Sin, the 'O' and the 'H' is for Opposite over Hypotenuse.
CAH- The 'C' is for Cos and the 'A' and the 'H' is for Adjacent over Hypotenuse.
TOA- The 'T' is for Tan, the 'O' and the 'A is for Opposite over Adjacent.
As you have the Opposite (the side opposite the angle we're looking for) and the Adjacent (the side next to the angle were looking for) we would be using Tan.
So first you would have to write:
Tanθ=3/4
Then because we want Theta (θ) on it's own we would have to do the inverse to 'undo' the equation. Tan-1 is the inverse of Tan.
θ=Tan-1 3/4
To find the answer you would have to put it in your calculator.
θ=36.9
Hope this helps :)
