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kumpel [21]
2 years ago
15

7/2 + x/2 = -5x + 5/3 solve for x

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
7 0

Answer:

give a heart and 5 stars

Step-by-step explanation:

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Solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​
ratelena [41]

Answer:

Solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​we get x=2 and y=-3

Solution set = {2,-3}

Step-by-step explanation:

We need to solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​

let:

3x-2y=12--eq(1)\\x+3y=-7 --eq(2)

Finding value of x from equation 2 and putting in eq(1)

From \ eq(2)\\x+3y=-7\\x=-7-3y

Putting value of x in eq(1)

3x-2y=12\\Put \ x=-7-3y\\3(-7-3y)-2y=12\\Solving\\-21-9y-2y=12\\-11y=12+21\\-11y=33\\y=\frac{33}{-11}\\y=-3

So, we get y=-3

Now put value of y in equation 2 to find value of x

x+3y=-7\\x+3(-3)=-7\\x-9=-7\\x=-7+9\\x=2

So, we get value of x =2

So, solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​we get x=2 and y=-3

Solution set = {2,-3}

4 0
2 years ago
1. Find the value of the power. (1/2)4"​
ioda

Answer:

2

Step-by-step explanation:

You would use PEMDAS( parentheses exponents multiply adding subtracting) (1/2)4.

^

o.5×4

^

2

5 0
2 years ago
Solve. −1.2z − 8.2 > −9.7
leonid [27]
<span>−1.2z − 8.2 > −9.7</span>
−1.2z > - 1.5
  z < 1.25


3 0
3 years ago
What is the distance between the following points?
likoan [24]

Answer:

11.

Step-by-step explanation:

9 right, and 2 up

7 0
2 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
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