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kumpel [21]
2 years ago
15

7/2 + x/2 = -5x + 5/3 solve for x

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
7 0

Answer:

give a heart and 5 stars

Step-by-step explanation:

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What is 9 divided by 28.08 plz help me ( i will give you 23 point)
andrey2020 [161]
The answer will be 3.12
8 0
3 years ago
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PLS HELP ME WITH 4!! (MUST SHOW WORK!!) *suppose to figure out what's in the missing box!* *LOTS OF POINTS!!*
MArishka [77]
-4(2.5y-3.25) - 15.25 = -10y + box
-4(-0.75y) - 15.25 = -10y + box
3y-15.25 = -10y + box
-7y-15.25 = box
box and/or y = -22.25

i'm not 100 percent sure of my answer, but I'm pretty confident. If i am wrong, then all you need to do is distribute in the beginning.
4 0
3 years ago
Fill in the blanks with the correct coefficient.
GaryK [48]

Answer:

the final answer is 2x²+17x-12

so to fill in the blank the first box will be 2 and the second box will be 12

6 0
2 years ago
4. [5 pts] Describe how and why the formula for permutations differs from the formula for combinations.
ivann1987 [24]

Answer:

They are different because of the order in the permutation matters. In combination, the order doesn't matter. In other words in a permutation 123 and 132 are different but in a combination are the same group (they have the same digits 1,2, and 3).

Step-by-step explanation:

The formula of the permutation is P(n,r)=\frac{n!}{(n-r)!}, when you are performing a permutation you pick r objects from a total of n, for the first pick you can choose from n, but for the second you have n-1, and this continues to your  pick number r in which you will choose from n-r+1, and the total of permutation is the multiplicación of this number of choices for each pick, like this:

n(n-1)(n-2)...(n-r+1)

If n!=n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1) and (n-r)!=(n-r)(n-r-1)(n-r-2)...(1)

\frac{n!}{(n-r)!}=\frac{n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1)}{(n-r)(n-r-1)(n-r-2)...(1)}

The factor equals above and under cancel each other.

\frac{n!}{(n-r)!}=\frac{n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1)}{(n-r)(n-r-1)(n-r-2)...(1)}\\\frac{n!}{(n-r)!}=n(n-1)(n-2)...(n-r+1)

In combination, the order of the element isn't important, so from the total of permutation you have to eliminate the ones with the same objects with different order and counting just once each group, when choosing r objects the total of permutation for a single group of r objects is: r(r-1)(r-2)...(1)=r!. If you divide the total of permutations of n taking r by r! you get the combinations (where the order is not important). The formula of the combination is C(n,r)=\frac{n!}{r!(n-r)!}.

4 0
4 years ago
A player at a basketball camp set a goal to make 55% if his shots. If he has 120 attempts, how many shots would he need to make
Pavel [41]

Answer: 66

Step-by-step explanation:

From the question, we are informed that a player at a basketball camp set a goal to make 55% if his shots and that he has 120 attempts.

The number of shots that he would he need to make in order to reach his goal will be 55% of 120. This will be:

= 55% × 120

= 55/100 × 120

= 0.55 × 120

= 66

He would need to make 66 shots

3 0
3 years ago
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