<span>Changing the grouping of the addends should not change the sum, according to the associative property of addition. You might group them differently with (50 + 3) + 47, so that you have 50 + (3 + 47). You might not regroup them with (16 + 4) + 5 rather than 16 + (4 + 5).</span>
Answer: 0.5507
Step-by-step explanation:
Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function
Since , the waiting time is in hours , then we can write 12 minutes as 
hour i.e.0.2 hour.
Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-
Hence, the required probability = 0.5507
If I understand the problem correctly
The blank on the left would be 14
and the blank on the top would be 350
9514 1404 393
Answer:
B. 3x^2 +11x -20 = 0
Step-by-step explanation:
For solutions p and q, the quadratic will be
(x -p)(x -q) = 0
We notice that the leading coefficients of the offered answer choices are greater than 1, so it will be convenient to use a value that "clears fractions."
(x -4/3)(x -(-5)) = 0
3(x -4/3)(x +5) = 0 . . . . multiply by 3 to clear the fraction
(3x -4)(x +5) = 0 . . . . . . clear the fraction
3x(x +5) -4(x +5) = 0 . . use the distributive property
3x^2 +15x -4x -20 = 0 . . . . use the distributive property again
3x^2 +11x -20 = 0 . . . . collect terms
_____
The constant in the product of factors is the product of roots:
(x -p)(x -q) = x^2 -(p+q)x +pq
Here, that would mean the constant would be (4/3)(-5) = -20/3.
If we compare the above quadratic to the standard form:
ax^2 +bx +c = 0
we find that we can divide the standard form equation by 'a' to get ...
pq = c/a
That is, c/a = -20/3, so we might start looking for an answer choice that has a leading coefficient of a=3 and a constant of c=-20.
Answer:
5 x
Step-by-step explanation:
if its scientific notation
