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1 year ago

Expand and simplify 3(5x+1)+5(5x-4)

Mathematics

1 answer:

SVEN [57.7K]1 year ago

8 0

Answer:

40x-17

Step-by-step explanation:

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X + 2y = 10 3x + 4y = 8 Which point is the solution to the system of equations?

bija089 [108]

Answer:

x = -12

y = 11

Step-by-step explanation:

i used substitution and let 'x' = 10 - 2y

3(10 - 2y) + 4y = 8

30 - 6y + 4y = 8

30 -2y = 8

-2y = -22

y = 11

x + 2(11) = 10

x + 22 = 10

x = -12

6 0

3 years ago

Answer...........................

Usimov [2.4K]

Answer:

9.9 years

Step-by-step explanation:

A = P e ^(rt)

Where A is the amount in the account

P is the amount invested

R is the interest rate

t is the time

P = 8500

r =7% = .07

A = 17000

Substituting into the equation

17000=8500 e^(.07t)

Divide each side by 8500

17000/8500=8500/8500 e^(.07t)

2 = e^(.07t)

Take the natural log of each side

ln (2) = ln e^(.07t)

ln(2) = .07t

Divide each side by .07

ln(2)/.07 = .07t/.07

ln(2)/.07 = t

9.902102579=t

Rounding to one decimal place

9.9 years

4 0

3 years ago

Read 2 more answers

Ship A and Ship B are 120 km apart when they pick up a distress call from another boat. Ship B estimates that they are 70 km awa

oksian1 [2.3K]

Answer:

147.5 km and 64.4 km

Step-by-step explanation:

a=120 km

b=70 km

β=28 degrees ( ∘)

b^2=(a^2)+(c^2)−2ac*cosβ

70^2 =(120^2 )+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )

(c^2 ) −211.907c+9500=0

note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use

p=1;q=−211.907;r=9500

D=(q^2 ) −4pr=(211.907^2 )−4⋅1⋅9500=6904.75561996

D>0

$c_{1,2}$ = (−q± $\sqrt{D}$ )/2p=(211.91± $\sqrt{6904.76}$ )/2

$c_{1,2}$ =105.95371114±41.5474295834

( $c_{1}$ −147.501140726)( $c_{2}$ −64.4062815596)=0

$c_{1}$ =147.501140726

$c_{2}$ =64.4062815596

5 0

3 years ago

For the function f(x)=5x2−5x, evaluate and simplify.

Marianna [84]

9514 1404 393

Answer:

10x -5 +5h

Step-by-step explanation:

Use the function definition with the given arguments.

$\dfrac{f(x+h)-f(x)}{h}=\dfrac{(5(x+h)^2-5(x+h))-(5x^2-5x)}{h}\\\\=\dfrac{(5(x^2+2hx+h^2)-5(x+h))-(5x^2-5x)}{h}\\\\=\dfrac{5x^2+10hx+5h^2-5x-5h-5x^2+5x}{h}=\dfrac{10hx-5h+5h^2}{h}\\\\=\boxed{10x-5+5h}$

7 0

2 years ago

(ab^2 x -b^4a^3)^2 What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

3 0

2 years ago

Expand and simplify 3(5x+1)+5(5x-4)​

Expand and simplify 3(5x+1)+5(5x-4)