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joja [24]
2 years ago
6

I NEED HELP can. someone help me please

Mathematics
1 answer:
Andrej [43]2 years ago
7 0

Answer:

A & E

10-11= - 1

4y-5y= - y

4x5=20

4 x 2y = 8y

-3 x 3y = - 9y

-3 x 7 = - 21

20-21= - 1

8y - 9y = - y

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Each polygon pair is similar. Find the missing side length
ohaa [14]

I'll do problem 1 to get you started.

The vertical sides are 3 and x for the left and right figures.

The horizontal sides are 15 and 60 for the left and right figures.

The corresponding sides form fractions which are equal (due to the nature of the similar polygons)

3/x = 15/60

3*60 = x*15 ... cross multiply

180 = 15x

15x = 180

x = 180/15 .... divide both sides by 15

x = 12

----------

Another way you can see this is note how the jump from 15 to 60 is "times 4", so the jump from 3 to x must also be "times 4" to keep the same proportion

3 ---> x = 3*4 = 12

Or you could set up the proportion

60/15 = x/3

4 = x/3

x/3 = 4

x = 3*4

x = 12

-----------

<h3>Final Answer: 12</h3>
3 0
3 years ago
Pls help me guys!<br> Thanks :D I'm really stuck
Katarina [22]
A) <
You are welcome and if someone else answers, mark me brainliest
5 0
3 years ago
Read 2 more answers
Evaluate √196 <br>A.11<br>B.12<br>C.13<br>D.14
ANTONII [103]

Hello :)

196 = 14.14 so the answer is D

169 = 13.13

144=12.12

121=11.11

Have a nice day :)

5 0
3 years ago
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Can someone please help me show my work for 6. And 7. I really need help and haft to show how I got the answers I’ll give the br
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Answer 6
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3 years ago
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