Answer:
![f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Step-by-step explanation:
![f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B1%29%5E3%5C%5C%5C%5Cy%3D%28x%2B1%29%5E3%5C%5C%5C%5Cx%3D%28y%2B1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B1%5C%5C%5C%5Cy%3D%5Csqrt%5B3%5D%7Bx%7D-1%5C%5C%20%5C%5Cf%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Graphing both inverses, they will be symmetrical about the line 
.
X=6
y=7
6+7
= 13
1/2(6) + 7
= 3 +7
=10
Answer:
-5 < x < 5
Step-by-step explanation:
|x| < 5
This can be split into two cases: x < 5 and -x < 5 because |x| could be either x or -x depending on whether x is positive, negative, or 0. Solving the second one we get x > -5 so the answer is -5 < x < 5.
Answer:
<u>f(x) = = (x + √2 i) (x - √2 i) (x - 2 ) (x + 1)</u>
Step-by-step explanation:
The given function is f(x) = x⁴ - x³ -2x -4
factor the polynomial function
f(x) = x⁴ - x³ -2x -4 = (x⁴ - 4) - (x³ + 2x ) ⇒ take (-) as a common from (- x³ -2x)
= (x² + 2 ) (x² - 2) - x (x² + 2) ⇒ take (x² + 2) as a common
= (x² + 2 ) ( x² - x - 2)
= (x + √2 i) (x - √2 i) (x -2 ) ( x+1)
Notes: (x⁴ - 4) = (x² + 2 ) (x² - 2)
(x² + 2)= (x + √2 i) (x - √2 i)
( x² - x - 2) = (x -2 ) ( x+1)
