If f(x) = 3 ^ x - 7 and g(x) = x ^ 2 + 11 , the value of f(2) - g(7) is:

Mathematics

1 answer:

Maurinko [17]3 years ago

4 0

Answer:

The value of $f(2) - g(7)=-58$

Step-by-step explanation:

We have

$f(x) = 3 ^ x - 7\\\\f(2) = 3 ^ 2 - 7\\\\=9-7\\\\=2\\\\g(x) = x ^ 2 + 11\\\\g(7) = 7 ^ 2 + 11\\\\=49+11\\\\=60\\\\f(2) - g(7)=2-60\\\\=-58$

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A) what is the simplified product of seven-fourths divided by eight-fifths as an improper fraction

Alex73 [517]

Answer:

First were going to put our numbers in perspective.

$\frac{7}{4}$ ÷ $\frac{8}{5}$

But to find the improper fraction, we have to cross multiply these numbers.

$\frac{7}{4}$ × $\frac{8}{5}$

7 x 5 = 35. 

4 x 8 = 32.

Now we have our improper fraction is $\frac{35}{32}$

To turn our improper fraction into a mixed number, we will use division.

We know that the 32 can only go into 35 one time. We also know that the bottom number always stays the same. So our equation will look somewhat like this.

$1\frac{?}{32}$

Now to fine the top number we will have to subtract 35 from 32 because we already know that 32 can go into 35 one time, so 35 - 32 = 3. So are mixed number will look like this.

$1\frac{3}{32}$