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Firlakuza [10]
2 years ago
10

Given that Ax - 4x² + 3x² + 4 = (x² - 2x + 1)(2x² + B) + C(x-1) + D for all values of x, evaluate A, B, C and D. Hence, deduce t

he remainder when Ar-4x+3x²+4 is divided by 2x² + B.
Mathematics
1 answer:
Scrat [10]2 years ago
5 0

SANA MAKATULONG

#CARRYONLEARNING

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Statements that can be proven by a logical sequence of statements is called a(n)
laila [671]
A)Theorem. every theorem can be proved.
6 0
3 years ago
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If one basket contains five bottles each weighing 7 1/4 ANSYS and the other basket has six apples each weighing 6 1/2 ounces woo
Tems11 [23]

<em>Question:</em>

<em>If one basket contains five bottles each weighing 7 1/4 and the other basket has six apples each weighing 6 1/2 ounces. Which basket is heavier and by how much ?</em>

Answer:

The basket of bottles weighs more than the basket of apples by 3\frac{3}{4} ounces

Step-by-step explanation:

Given

Bottles = 5

Weight(Bottle) = 7\frac{1}{4}

Apples = 6

Weight(Apple) = 6\frac{1}{2}

Required

Determine which basket is heavy

and by how much?

First, we need the total weight of each basket.

For the bottles' basket

Total\ Weight = Weight * Bottles

Total\ Weight = 7\frac{1}{4} * 5

Total\ Weight = \frac{29}{4} * 5

Total\ Weight = \frac{29 * 5}{4}

Total\ Weight = \frac{145}{4}

Total\ Weight = 36\frac{1}{4}

For the bottles' basket

Total\ Weight = Weight * Apples

Total\ Weight = 6\frac{1}{2} * 5

Total\ Weight = \frac{13}{2} * 5

Total\ Weight = \frac{13* 5}{2}

Total\ Weight = \frac{65}{2}

Total\ Weight = 32\frac{1}{2}

By comparing both total weights, 36\frac{1}{4} > 32\frac{1}{2}

Hence:

The basket of bottles weighs more than the basket of apples

Calculating the difference:

Difference = 36\frac{1}{4} - 32\frac{1}{2}

Difference = \frac{145}{4} - \frac{65}{2}

Difference = \frac{145 - 130}{4}

Difference = \frac{15}{4}

Difference = 3\frac{3}{4}

Hence:

It weighs more by 3\frac{3}{4} ounces

8 0
3 years ago
The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi
eimsori [14]

Answer:

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=4.2 represent the sample mean  

s=1.4 represent the sample standard deviation  

n=16 represent the sample selected  

\alpha=0.05 significance level  

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:    

Null hypothesis:\mu = 3.6    

Alternative hypothesis:\mu \neq 3.6    

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with df=n-1=16-1=15 degrees of freedom. The value for \alpha=0.05 and \alpha/2=0.025 so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got t_{crit}=\pm 2.131    

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

Conclusion    

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0
3 years ago
The distance from Earth to the moon is about 4*10 fifth power kilometers. The distance from Earth to Mars is about 5*10 the seve
uysha [10]

Answer: distance from earth to moon is 4x10^5= 4,000,000

The distance from Earth to Mars is about 5x10^7= 50,000,000.

Step-by-step explanation:

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3 years ago
Write a real world problem for the equation 11x =385.
bagirrra123 [75]
Real world problem for 11x = 385

Sam brought home 385 packs of string for the party. At the party, Sam invites 11 people, and wants to give each person the same amount of string. How much string does each person get?
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