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Katen [24]
4 years ago
10

2/10times6/10. Please help

Mathematics
2 answers:
babunello [35]4 years ago
8 0

Answer:

I believe the answer is 1 2/10

Hope this helps!



FromTheMoon [43]4 years ago
6 0

The answer is 3/25


you simplify 2/10 to 1/5

and simplify 6/10 to 3/5.

Then multiply the denominators

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Find the absolute maximum of m(t)=t^3-12t^2-144t and justify your answer​
ruslelena [56]

Answer:

Step-by-step explanation:

m(t)=t³-12t²-144t

Take the derivative of t:

t'=3t²-24t-144

Set it to 0:

3t²-24t-144=0

Solve for t:

t²-8t-48=0

(t-12)(t+4)=0

t=12 or -4

On a graph, you'll find that the maximum value occurs at t=-4 ..............

3 0
3 years ago
What is 18/48 simplify
Y_Kistochka [10]
Hmm they're both even numbers so maybe we can start by cutting each number in half.
\rm \dfrac{18}{48}=\dfrac{9\cdot2}{24\cdot2}=\dfrac{9}{24}
18 and 48 had 2 as a common factor.
So factoring a 2 out of each number was the same as cutting each number in half. Try to do something similar with the 9 and 24. They each have something in common.
4 0
3 years ago
Read 2 more answers
6/5 pls help as fast as possible
11Alexandr11 [23.1K]

Answer: 6 divided by 5 is 1.2

Step-by-step explanation: I used Siri lol

4 0
2 years ago
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How many times bigger is 6.4*10^9 than 1.3*10^9
sukhopar [10]

Answer:

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%20%7D%5E%7B2%7D%20%3D%20%20%7B16%7D%5E%7Bx%3F%7D%20%20%20" id="TexFormula1" title=" {x
lora16 [44]
X is -1/2 . Using the Lambert W function.
x^2=16^x => x^2=(2^4)^x
x^2=2^4x => x=2^2x
x=(e^in(2))^2x => x=e^2in(2)x
e^2in(2)x1/x=1
xe^-2in(2)x=1 /*1
-xe^-2in(2)x=-1
-2in(2)xe^-2in(2)x=-2in(2)
W(-2in(2)xe^-2in2x)=W(-2in(2))
-2in(2)x=W(-2in(2))
X=-W(-2in(2))/2in(2)
5 0
3 years ago
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