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2 years ago

15

PLS HELP THIS THE ANSWER To travel between Pembroke and Quinnville, a person can choose one of two routes.

1 answer:

mrs_skeptik [129]2 years ago

8 0

Answer:

Joe arrived first

Step-by-step explanation:

Joe drove 150 miles 40miles per hour soo he arrived in 3:45

But frank drove 4 hour

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A number card from 1 to 8 is randomly chosen. What is p(5)

Nina [5.8K]

the answer is 1/8. I double checked

7 0

3 years ago

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Please help me friends

adoni [48]

Answer: x ≥ 4

<u>Step-by-step explanation:</u>

x + 10 ≥ 14

Subtract 10 from both sides of the equation:

x ≥ 4

Graphing:

> and < symbols represent an open dot

≥ and ≤ symbols represent a closed dot

Since the solution is: x ≥ 4, we will use a closed dot and the arrow will point to the right of 4.

4 ·------------→

4 0

3 years ago

Can anyone solve this? Please i need help on these. 50 points for the person who answers!

suter [353]

Answer:

a. k = 8

b. k = 95

c. k = 13.95

d. k = 40

Step-by-step explanation:

4 0

2 years ago

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(9 – 6i) × m = 9 – 6i<br> What is m?<br><br> 0<br><br> 1<br><br> 9 + 6i<br><br> -9 + 6i

GuDViN [60]

Answer:

1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers