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forsale [732]
2 years ago
5

A catalyst increases the rate of a chemical reaction by

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
5 0

Answer:

Lowering the activation energy

Explanation:

A catalyst does not participate in the reaction, instead it offers the reaction an alternative pathway by lowering the activation energy. This new pathway is faster and the rate of reaction is increased.

You might be interested in
Whitney's lung capacity was measured as 3.3 l at a body temperature of 37 ∘c and a pressure of 746 mmhg . how many moles of oxyg
myrzilka [38]

the ideal gas equation is PV=nRT  
 where P=pressure  
 V=Volume  
 n=no. of moles  
 R=universal gas constant  
 T=temperature  
 The universal gas constant (R) is 0.0821 L*atm/mol*K    
 a pressure of 746 mmhg =0.98 atm= 1 atm (approx)   
 T=37 degrees Celsius =37+273=310 K (convert it to Kelvin by adding 273)    
 V=0.7 L (only getting oxygen, get 21% of 3.3L)    
 Solution:  
 (1 atm)(0.7 L)=n(0.0821 L*atm/mol*K)(310 K)  
 0.7 L*atm=n(25.451 L*atm/mol)  
 n=0.0275 mole   
 Answer:   
n=0.0275 mole of oxygen in the lungs.
4 0
2 years ago
If you wanted to measure in irregular object's volume, which device would you use?
EleoNora [17]

Answer:

a beaker

Explanation:

3 0
3 years ago
Who answers the three economic questions in a market economy? How is this different from command economy?
Natali [406]

Answer:

Market economies are characterized by their free markets. Examples are the United States and the United Kingdom.

  • That's pretty clear. What it means is that they trust in the free market and its operation to answer the questions of what to produce, how much to produce, and for whom.

Command economies are characterized by their control of markets. Examples are China and North Korea.

  • They rely on the government, <em>not the free market itself, </em>to control what should be produced. This makes for a more strict system that can pay off in the long run, but can also run the risk of being heavy-handed.

6 0
3 years ago
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 ºC. Assuming that the pressure remains constant, what tem
Ludmilka [50]

Answer:

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

Explanation:

Step 1: Data given

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L

Temperature = 198 °C = 471 K

The volume will be reduced to 2.50 L

Step 2 Calculate the new temperature via Charles' law

V1/T2 = V2/T2

⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L

⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K

⇒with V2 = the reduced volume of the gas = 2.50 L

⇒with T2 = the new temperature = TO BE DETERMINED

5.10 L / 471 K = 2.50 L / T2

T2 = 2.50 L / (5.10 L / 471 K)

T2 = 230.9 K = -42.1

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

8 0
3 years ago
If we know this is a second-order reaction, what is the rate law?
Pavel [41]

Answer:

The rate is a mathematical relationship obtained by comparing reaction rate with reactant concentrations.

6 0
3 years ago
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