The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
HOW TO CALCULATE VOLUME OF ETHANOL:
- According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.
- If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:
- Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
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First, let's state the chemical reaction:
We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:
The calculation would be:
And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:
The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
Answer:
1. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻
2. HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
3. H₂CO₃ → H₂O + CO₂
Basic solution
Explanation:
Brønsted Lowry theory:
Acid → Release a proton
Base → Accept a proton
1. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻
Carbonate takes a proton from the water
2. HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
Bicarbonate takesa proton from the water to produce carbonic acid.
3. H₂CO₃ → H₂O + CO₂
Carbonate acid decomposes into CO₂ and H₂O
In the first reaction, when the carbonate takes a proton from the water, water releases OH⁻, so the solution is basic.
