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Lostsunrise [7]
3 years ago
5

Morgan bought candy for $.95, an eraser for $.15, and 2 pencils for $.40 each. (a) how much did the pencils cost? (b) how much d

id she spend in all? (c) how much change did she get from $5.00
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Step-by-step explanation:

A

1 pencil costs 0.40 dollars.

1 pencils cost 2 times 0.40 = .80 dollars

B

Candy     0.95

eraser     0.15

2 pencils <u>0.80</u>

Total        1.90                                          Add  

C

She started with   5.00 dollars

She spent             <u> 1.90 </u>dollars               Subtract

Here change was  3.10 dollars.

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Trent lift weights 7 days a week. He spends 18 minutes lifting weights on Monday, 29 minutes on Tuesday, 40 minutes on Wednesday
Ostrovityanka [42]

He lifts for 11 more minuets each day.

51 + 11 = 62

He lifted for 62 minuets on Friday.

62 + 11 = 73

He lifted for 73 minuets on Saturday.

6 0
3 years ago
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
4 years ago
A study shows that 78​% of the population of all calculus students consider calculus an exciting subject. Suppose 20 students ar
alexdok [17]

Answer:

0.046145 = 4.6145%

Step-by-step explanation:

We need to find the probability of 19 or 20 (all) students considering calculus to be an exciting subject, so first we find the probability for 19 students, then for 20 students, and we sum these probabilities.

The probability of the student NOT considering calculus to be an exciting subject is 1 - 0.78 = 0.22

For 19 students, we also have to calculate a combination of 20 choose 19, as these 19 students can be in different "position" among the 20 students, so:

C(20,19) = 20!/19! = 20

Probability of 19 students considering calculus to be an exciting subject:

C(20,19) * 0.78^19 * 0.22^1 = 0.039196756

Probability of 20 students considering calculus to be an exciting subject:

C(20,20) * 0.78^20 = 1 * 0.78^20 = 0.006948516

The final probability is:

0.039196756 + 0.006948516 = 0.046145272 = 4.6145272%

Rounding to six decimal places: 0.046145 = 4.6145%

5 0
3 years ago
SO anyways :))))
artcher [175]

Answer:

1 / 8², B

Step-by-step explanation:

8 / 8³

8³ = 8*8*8

So, the equation can also be written as:

8 / 8*8*8

divide the numerator and denominator by 8.

1 / 8*8

This is equal to:

1 / 8²

The answer is B.

7 0
3 years ago
School rules permit no fewer than 2 teachers per 25 students. There are at least 245 students enrolled in the school. If x repre
NISA [10]
First, let's write down this inequality:
<span>There are at least 245 students enrolled in the school.

 y≥245

This inequality says what the sentence says!

now, the number of teachers must be:
x≥2*(y/25)
 (two times the number of groups of students of 25!)

so those two inequalities, taken together will be the answer!
</span>
6 0
3 years ago
Read 2 more answers
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