Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
Answer:
bool b = isupper(x);
Step-by-step explanation:
I have written the expression for a char variable x.The isupper(x) will return true if the character x is upper case and false if the character x is lower case.
I have stored the returned value to a bool variable b .So the value of variable b will be true only when the x is in uppercase and false when b is lower case.
Answer:
No answer
Step-by-step explanation:
5x-20-X+9
7x-20+9
7x-11
Answer:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Step-by-step explanation:
Let's test it
So we do indeed have the inverse function, so using that we can plug in the values requested:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Formula for perimeter a+b+a+b
12+5+12+5= 17+17= 34 .34=P
