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pochemuha
3 years ago
10

Given sin (-theta) = 1/5 and tan theta = sqrt.6/12

Mathematics
1 answer:
stich3 [128]3 years ago
3 0

Given  sin (\theta) = \frac{1}{5}, andtan \theta = \frac{\sqrt{6} }{12}, then:

cos\theta=\frac{2\sqrt{6} }{5}

<h3> Computations on trigonometric identities</h3>

From the details provided:

sin (\theta) = \frac{1}{5}\ \\\\tan \theta = \frac{\sqrt{6} }{12} \times \frac{\sqrt{6} }{\sqrt{6} }\\\\tan \theta = \frac{\sqrt{6} \times \sqrt{6} }{12 \times \sqrt{6} }\\\\tan \theta =\frac{1}{2\sqrt{6} }

From the relationship above:

Opposite = 1

Adjacent = 2\sqrt{6}

Hypotenuse = 5

cos\theta=\frac{Adjacent}{Hypotenuse} \\\\cos\theta=\frac{2\sqrt{6} }{5}

Learn more on trigonometry here: brainly.com/question/20519838

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