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strojnjashka [21]
3 years ago
10

ANSWER THESE TWO QUESTIONS PLEASE THANK YOU

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

1) $63.60

2) y=8x-6

Step-by-step explanation:

1) $233.20 divided 11 hours is a hourly rate of $21.20. $21.20 multiplied by 3 hours is $63.60.

2) To find the slope you need \frac{y_{2} -y_{1}}{x_{2}-x_{1}}. (10-2)/(2-1) is 8. The slope is 8. So you have y=8x+b. To find b just plug in a point and solve. 2=8(1)+b. B= -6. y=8x-6

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Is 4.47214 a rational number
Agata [3.3K]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The sum of 3 consecutive odd numbers is 51. What is the second number in this sequence?
Veseljchak [2.6K]
Assume the second number is x, then the other two are x - 2, x + 2

So x-2 + x + x + 2 = 51

-> 3x = 51

-> x = 17
7 0
3 years ago
"A line that goes through (4, 7) and (-2, 1)"
Olenka [21]
Y= x + 3
1. Find the gradient(slope)

1 - 7 / - 2 - 4
=1

2. Find the y. Intercept ( c )
Y = x + c
Replace by any of the two coordinates given (4 , 7 )
7 = 4 + c
C= 3

Equation => Y = x + 3
6 0
3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
Alice was having a conversation
Akimi4 [234]
What's the question..???
4 0
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