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2 years ago

Please help me with work

Mathematics

1 answer:

igomit [66]2 years ago

7 0

1. the equation is y=mx+b. m= slope and b= y-intercept so your answer should be y=2/3x+2

2. point-slope form is y-y1/x-x1=m answer is y+4=-1(x-1)

3. i give up im sorry my brain is fried ;-;

4.uhh i graphed it and attached an image lol

dang i- cant do no more math today lol sorry good luck

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Dafna1 [17]

Answer:

Step-by-step explanation:

1. no

2. yes

3. yes

4. yes

5. 5.2

6. 4.5

7. 2.5

8. 16

8 0

2 years ago

Help need answer please

antiseptic1488 [7]

Answer:

59.5

Step-by-step explanation:

1st tree to shadow ratio: 17:10

Plug the numbers in to get x:35

17:10=x:35

17/10=x/35

Multiply both sides by 35

595/10=x

59.5=x

5 0

2 years ago

solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$

Thus, the system of three equations is

$\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.$

From the last equation:

$y=-6$

Substitute it into the second equation:

$16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3$

Substitute y = -6 and z = -3 into the first equation:

$x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5$

7 0

3 years ago

What does proportion mean

kompoz [17]

A number considered in relative relation to a whole number.

4 0

2 years ago

Read 2 more answers

If n(A) = P and n(B)=q then n(AxB) is (a ) p (b ) q ( c ) p+q ( d ) pq

Butoxors [25]

By way of example, suppose A = {1, 2, 3} and B = {a, b, c}. Then the Cartesian product of A and B is

A × B = {{1, a}, {1, b}, {1, c}, {2, a}, {2, b}, {2, c}, {3, a}, {3, b}, {3, c}}

That is, each element in A gets a pairing with each element in B, and for each pairing you have n(A) choices for the first element and n(B) choices for the second element.

So if n(A) = p and n(B) = q, then n(A × B) = pq.

6 0

3 years ago